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python实现的简单文本类游戏实例

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本文实例讲述了python实现的简单文本类游戏实现方法。分享给大家供大家参考。具体实现方法如下:

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############################################################
# - My version on the game "Dragon Realm".
# - taken from the book "invent with python" by Al Sweigart.
# - thanks for a great book Mr Sweigart.
# - this code takes advantage of python 3.
############################################################
#files.py
import random
import time
print ( '\n\n[--system--] one file is bad the other is good ..guess the right one.\n' )
print ( '\n\nconnecting....' )
time.sleep( 1 )
print ( '....' )
time.sleep( 1 )
print ( '....' )
time.sleep( 1 )
print ( '....' )
time.sleep( 1 )
print ( '\nconnection established' )
def displayIntro():
   print ( '------------' )
   print ( 'SYSTEM FILES' )
   print ( '------------\n' )
   print ( '1.) file.' )
   print ( '2.) file.\n' )
def chooseOption():
   option = ''
   while option ! = '1' and option ! = '2' :
     print ( 'which file to download? 1 or 2' )
     option = input ( 'user:> ' )
   return option
def checkOption(chosenOption):
   print ( '\nintialising download....' )
   time.sleep( 1 )
   print ( 'accessing file....' )
   time.sleep( 1 )
   print ( 'downloading....' )
   time.sleep( 1 )
   print ( '....' )
   time.sleep( 1 )
   print ( '....' )
   time.sleep( 1 )
   goodfile = random.randint( 1 , 2 )
   if chosenOption = = str (goodfile):
     print ( '\ndownload complete.' )
     print ( '\nGAME OVER' )
   else :
     print ( '\nfile corrupt' )
     print ( 'system infected.' )
     print ( '\nGAME OVER' )
playAgain = 'yes'
while playAgain = = 'yes' :
   displayIntro()
   optionNumber = chooseOption()
   checkOption(optionNumber)
   print ( '\ndownload again? .... (yes or no)' )
   playAgain = input ( 'user:> ' )
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############################################################
# - My version of the game "guess the number".
# - taken from the book "invent with python" by Al Sweigart.
# - thanks for a great book Mr Sweigart.
# - this code takes advantage of python 3.
############################################################
# -NOTE - this program will crash if a number is not typed.
#digitcode.py
import random
import time
guessesTaken = 0
print ( '\n\n\n\n\n[--system--] enter code in 15 trys to avoid lockout\n' )
print ( '\nconnecting....' )
time.sleep( 1 )
print ( '....' )
time.sleep( 1 )
print ( '....' )
time.sleep( 1 )
print ( '....' )
time.sleep( 1 )
print ( 'connection established\n' )
print ( '---------------------' )
print ( ' MAINFRAME - LOGIN ' )
print ( '---------------------' )
print ( '\nenter 3 digit access code..' )
number = random.randint( 000 , 999 )
while guessesTaken < 15 :
   print ()
   guess = input ( 'user:> ' )
   guess = int (guess)
   guessesTaken = guessesTaken + 1
   if guess < number:
     print ( '\nACCESS - DENIED -code to low' )
   if guess > number:
     print ( '\nACCESS - DENIED -code to high' )
   if guess = = number:
     break
if guess = = number:
   guessesTaken = str (guessesTaken)
   print ( '\nverifying ....' )
   time.sleep( 1 )
   print ( '\nauthenticating ....' )
   time.sleep( 1 )
   print ( '....' )
   time.sleep( 1 )
   print ( '....' )
   time.sleep( 1 )
   print ( '\nACCESS - GRANTED' )
   print ( '\nGAME OVER\n' )
   exit( 0 )
if guess ! = number:
   number = str (number)
   print ( '\n....' )
   time.sleep( 1 )
   print ( '\n....' )
   time.sleep( 1 )
   print ( '\nSYSTEM LOCKED -the code was ' + number)
   print ()
   exit( 0 )

希望本文所述对大家的Python程序设计有所帮助.

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