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net.sf.saxon.expr.XPathContextMajor.getURIResolver()方法的使用及代码示例

转载 作者:知者 更新时间:2024-03-20 19:03:40 30 4
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本文整理了Java中net.sf.saxon.expr.XPathContextMajor.getURIResolver()方法的一些代码示例,展示了XPathContextMajor.getURIResolver()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。XPathContextMajor.getURIResolver()方法的具体详情如下:
包路径:net.sf.saxon.expr.XPathContextMajor
类名称:XPathContextMajor
方法名:getURIResolver

XPathContextMajor.getURIResolver介绍

[英]Get the URI resolver. This gets the local URIResolver set in the XPathContext if there is one; if not, it gets the URIResolver from the Controller (which itself defaults to the one set in the Configuration).
[中]获取URI解析器。这将获取XPathContext中的本地URIResolver集(如果有);如果没有,它将从控制器(其本身默认为配置中设置的)获取URIResolver。

代码示例

代码示例来源:origin: net.sf.saxon/Saxon-HE

/**
 * Get the URI resolver.
 *
 * @return the user-supplied URI resolver if there is one, or null otherwise. If no URIResolver
 * has been set locally, the URIResolver in the Controller is returned; this in turn defaults
 * to the URIResolver set in the Configuration.
 * @since 9.2. Changed in 9.6 to use a local URIResolver.
 */
public URIResolver getURIResolver() {
  return contextObject.getURIResolver();
}

代码示例来源:origin: org.apache.servicemix.bundles/org.apache.servicemix.bundles.saxon

/**
 * Get the URI resolver.
 *
 * @return the user-supplied URI resolver if there is one, or null otherwise. If no URIResolver
 * has been set locally, the URIResolver in the Controller is returned; this in turn defaults
 * to the URIResolver set in the Configuration.
 * @since 9.2. Changed in 9.6 to use a local URIResolver.
 */
public URIResolver getURIResolver() {
  return contextObject.getURIResolver();
}

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