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org.apache.hadoop.ha.ZKFailoverController.waitForActiveAttempt()方法的使用及代码示例

转载 作者:知者 更新时间:2024-03-14 16:54:49 26 4
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本文整理了Java中org.apache.hadoop.ha.ZKFailoverController.waitForActiveAttempt()方法的一些代码示例,展示了ZKFailoverController.waitForActiveAttempt()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。ZKFailoverController.waitForActiveAttempt()方法的具体详情如下:
包路径:org.apache.hadoop.ha.ZKFailoverController
类名称:ZKFailoverController
方法名:waitForActiveAttempt

ZKFailoverController.waitForActiveAttempt介绍

[英]Wait until one of the following events:

  • Another thread publishes the results of an attempt to become active using #recordActiveAttempt(ActiveAttemptRecord)
  • The node enters bad health status
  • The specified timeout elapses
    [中]等待以下事件之一:
    *另一个线程使用#recordActiveAttempt(ActiveAttemptRecord)发布试图激活的结果
    *节点进入不良运行状态
    *指定的超时已过

代码示例

代码示例来源:origin: org.apache.hadoop/hadoop-common

ActiveAttemptRecord attempt = waitForActiveAttempt(timeout + 60000);

代码示例来源:origin: com.github.jiayuhan-it/hadoop-common

ActiveAttemptRecord attempt = waitForActiveAttempt(timeout + 60000);

代码示例来源:origin: io.hops/hadoop-common

ActiveAttemptRecord attempt = waitForActiveAttempt(timeout + 60000);

代码示例来源:origin: ch.cern.hadoop/hadoop-common

ActiveAttemptRecord attempt = waitForActiveAttempt(timeout + 60000);

代码示例来源:origin: io.prestosql.hadoop/hadoop-apache

ActiveAttemptRecord attempt = waitForActiveAttempt(timeout + 60000);

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