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org.json.simple.parser.Yylex.yylex()方法的使用及代码示例

转载 作者:知者 更新时间:2024-03-14 13:02:49 30 4
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本文整理了Java中org.json.simple.parser.Yylex.yylex()方法的一些代码示例,展示了Yylex.yylex()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Yylex.yylex()方法的具体详情如下:
包路径:org.json.simple.parser.Yylex
类名称:Yylex
方法名:yylex

Yylex.yylex介绍

[英]Resumes scanning until the next regular expression is matched, the end of input is encountered or an I/O-Error occurs.
[中]继续扫描,直到下一个正则表达式匹配、遇到输入结束或发生I/O错误。

代码示例

代码示例来源:origin: com.googlecode.json-simple/json-simple

private void nextToken() throws ParseException, IOException{
  token = lexer.yylex();
  if(token == null)
    token = new Yytoken(Yytoken.TYPE_EOF, null);
}

代码示例来源:origin: i2p/i2p.i2p

private void nextToken() throws ParseException, IOException{
  token = lexer.yylex();
  if(token == null)
    token = new Yytoken(Yytoken.TYPE_EOF, null);
}

代码示例来源:origin: fangyidong/json-simple

private void nextToken() throws ParseException, IOException{
  token = lexer.yylex();
  if(token == null)
    token = new Yytoken(Yytoken.TYPE_EOF, null);
}

代码示例来源:origin: childe/hangout

private void nextToken() throws ParseException, IOException{
  token = lexer.yylex();
  if(token == null)
    token = new Yytoken(Yytoken.TYPE_EOF, null);
}

代码示例来源:origin: pstehlik/gelf4j

private void nextToken() throws ParseException, IOException{
  token = lexer.yylex();
  if(token == null)
    token = new Yytoken(Yytoken.TYPE_EOF, null);
}

代码示例来源:origin: stackoverflow.com

while ((t = yy.yylex()) != null) {
 String text = t.mText;

代码示例来源:origin: BiglySoftware/BiglyBT

token=lexer.yylex();
if(token==null)
  token=new Yytoken(Yytoken.TYPE_EOF,null);

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