gpt4 book ai didi

com.zsmartsystems.zigbee.ZigBeeApsFrame.getSourceEndpoint()方法的使用及代码示例

转载 作者:知者 更新时间:2024-03-15 14:03:31 28 4
gpt4 key购买 nike

本文整理了Java中com.zsmartsystems.zigbee.ZigBeeApsFrame.getSourceEndpoint()方法的一些代码示例,展示了ZigBeeApsFrame.getSourceEndpoint()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。ZigBeeApsFrame.getSourceEndpoint()方法的具体详情如下:
包路径:com.zsmartsystems.zigbee.ZigBeeApsFrame
类名称:ZigBeeApsFrame
方法名:getSourceEndpoint

ZigBeeApsFrame.getSourceEndpoint介绍

暂无

代码示例

代码示例来源:origin: zsmartsystems/com.zsmartsystems.zigbee

command.setSourceAddress(new ZigBeeEndpointAddress(apsFrame.getSourceAddress(), apsFrame.getSourceEndpoint()));
command.setDestinationAddress(
    new ZigBeeEndpointAddress(apsFrame.getDestinationAddress(), apsFrame.getDestinationEndpoint()));

代码示例来源:origin: zsmartsystems/com.zsmartsystems.zigbee

@Override
public void sendCommand(final ZigBeeApsFrame apsFrame) {
  ConBeeEnqueueSendDataRequest request = new ConBeeEnqueueSendDataRequest();
  request.setRequestId(apsFrame.getApsCounter());
  request.setClusterId(apsFrame.getCluster());
  switch (apsFrame.getAddressMode()) {
    case DEVICE:
      request.setDestinationAddress(
          new ZigBeeEndpointAddress(apsFrame.getDestinationAddress(), apsFrame.getDestinationEndpoint()));
      request.setDestinationAddressMode(ConBeeAddressMode.NWK);
      if (apsFrame.getDestinationAddress() > 0xfff8) {
        //
        request.setTxOptions(0);
      }
      break;
    case GROUP:
      request.setDestinationAddress(new ZigBeeGroupAddress(apsFrame.getDestinationAddress()));
      request.setDestinationAddressMode(ConBeeAddressMode.GROUP);
      break;
    default:
      break;
  }
  request.setProfileId(apsFrame.getProfile());
  request.setRadius(apsFrame.getRadius());
  request.setSourceEndpoint(apsFrame.getSourceEndpoint());
  // request.setTxOptions(txOptions);
  request.setAdsuData(apsFrame.getPayload());
  conbeeHandler.queueFrame(request);
}

28 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com