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org.jetbrains.yaml.YAMLFileType类的使用及代码示例

转载 作者:知者 更新时间:2024-03-13 13:16:59 27 4
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本文整理了Java中org.jetbrains.yaml.YAMLFileType类的一些代码示例,展示了YAMLFileType类的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。YAMLFileType类的具体详情如下:
包路径:org.jetbrains.yaml.YAMLFileType
类名称:YAMLFileType

YAMLFileType介绍

暂无

代码示例

代码示例来源:origin: Haehnchen/idea-php-symfony2-plugin

@NotNull
public static PsiFile createDummyFile(Project p, String fileText) {
  return PsiFileFactory.getInstance(p).createFileFromText("DUMMY__." + YAMLFileType.YML.getDefaultExtension(), YAMLFileType.YML, fileText, System.currentTimeMillis(), false);
}

代码示例来源:origin: Haehnchen/idea-php-symfony2-plugin

@NotNull
  private PsiElement createYamlFile(@NotNull String content) {
    return PsiFileFactory.getInstance(getProject()).createFileFromText("DUMMY__." + YAMLFileType.YML.getDefaultExtension(), YAMLFileType.YML, content);
  }
}

代码示例来源:origin: Haehnchen/idea-php-symfony2-plugin

/**
 * @see TwigUtil#getTwigGlobalsFromYamlConfig
 */
public void testGetTwigGlobalsFromYamlConfig() {
  String content = "twig:\n" +
    "    globals:\n" +
    "       ga_tracking: '%ga_tracking%'\n" +
    "       user_management: '@AppBundle\\Service\\UserManagement'\n"
    ;
  YAMLFile yamlFile = (YAMLFile) PsiFileFactory.getInstance(getProject())
    .createFileFromText("DUMMY__." + YAMLFileType.YML.getDefaultExtension(), YAMLFileType.YML, content, System.currentTimeMillis(), false);
  Map<String, String> globals = TwigUtil.getTwigGlobalsFromYamlConfig(yamlFile);
  assertEquals("%ga_tracking%", globals.get("ga_tracking"));
  assertEquals("@AppBundle\\Service\\UserManagement", globals.get("user_management"));
}

代码示例来源:origin: Haehnchen/idea-php-symfony2-plugin

.createFileFromText("DUMMY__." + YAMLFileType.YML.getDefaultExtension(), YAMLFileType.YML, content, System.currentTimeMillis(), false);

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