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147. Insertion Sort List 对链表进行插入排序

转载 作者:大佬之路 更新时间:2024-01-31 14:20:34 25 4
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题目地址:https://leetcode.com/problems/insertion-sort-list/description/

题目描述:

Sort a linked list using insertion sort.

 

Agraphical example of insertion sort. The partial sorted list (black) initially contains only the first element in the list. With each iteration one element (red) is removed from the input data and inserted in-place into the sorted list

Algorithm of Insertion Sort:

Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. At each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted list, and inserts it there. It repeats until no input elements remain.

Example 1:

Input: 4->2->1->3
Output: 1->2->3->4

Example 2:

Input: -1->5->3->4->0
Output: -1->0->3->4->5

题目大意

使用插入排序,对链表进行排序。

解题方法

这个算链表里边的难题了,其实就是模拟题目中图的过程,稍微有点复杂的就是指针的操作。参考了:链表插入排序open in new window里的做法,链表操作多用几个指针就方便很多了。

# Definition for singly-linked list.
# class ListNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution(object):
    def insertionSortList(self, head):
        """
        :type head: ListNode
        :rtype: ListNode
        """
        if not head or not head.next: return head
        root = TreeNode(0)
        root.next = head
        while head.next:
            if head.val <= head.next.val:
                head = head.next
            else:
                temp = head.next
                q = root
                head.next = head.next.next
                while q.next and q.next.val < temp.val:
                    q = q.next
                temp.next = q.next
                q.next = temp
        return root.next

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