c++ - 如何从用户那里获取多个数字并将偶数加在一起并乘以奇数？

Question

我想编写一个程序，接受 5 个输入并将偶数相加并乘以奇数，但在知道哪个数是奇数和哪个数是偶数之后，我不知道该怎么做。

#include<iostream>

using namespace std;

int main(){
   
 int a, b, c, d, e, sum1, sum2, sum3, sum4, sum5, sum6, sum7, sum8, sum9, sum10;
    
    cout<<"Please Enter 5 Integers\t:\t";
    cin>>a>>b>>c>>d>>e;
    
    if(a%2==0 && b%2==0)
    {
        cout<<a+b;
        sum1 = a+b;
    }
    
    if(a%2==0 && c%2==0)
    {
        cout<<a+c;
        sum2 = a+c;
    }
    
    if(a%2==0 && d%2==0)
    {
        cout<<a+d;
        sum3 = a+d;
    }
    
    if(a%2==0 && e%2==0)
    {
        cout<<a+e;
        sum4 = a+e;
    }
    
    if(b%2==0 && c%2==0)
    {
        cout<<b+c;
        sum5 = b+c;
    }
    
    if(b%2==0 && d%2==0)
    {
        cout<< b+d;
        sum6 = b+d;
    }
    
    if(b%2==0 && e%2==0)
    {
        cout<<b+e;
        sum7 = b+e;
    }
    
    if(c%2==0 && d%2==0)
    {
        cout<< c+d;
        sum8 = c+d;
    }
    
    if(c%2==0 && e%2==0)
    {
        cout<<c+e;
        sum9 = c+e;
    }
    
    if(d%2==0 && e%2==0)
    {
        cout<<d+e;
        sum10 = d+e;
    }
    
    return 0;
}

Answer 1

您不需要所有这些变量，当然也不需要一次检查每个变量组合。一个简单的循环就足够了。

尝试更像这样的东西:

#include <iostream>
using namespace std;

int main(){
   
    int number, sum = 0, product = 1;
    
    cout << "Please Enter 5 Integers\t:\t";

    for(int i = 0; i < 5; ++i)
    {
        cin >> number;
    
        if (number % 2 == 0)
            sum += number;
        else
            product *= number;
    }
    
    cout << sum << ' ' << product << endl;

    return 0;
}