java - 从 Double.toLongBits 创建的 long 中获取 double

Question

有没有办法将我从 Double.toLongBits 得到的 long 反转为 Double？
以下不起作用:

Double n = 171.30672219;
System.out.println(Double.doubleToLongBits(n));
System.out.println(new Double(Double.doubleToLongBits(n)));  

这打印:

4640231336019091517
4.6402313360190915E18

虽然我想取回 171.30672219

Answer 1

作为documentation对于 doubleToLongBits 说:

In all cases, the result is a long integer that, when given to the longBitsToDouble(long) method, will produce a floating-point value the same as the argument to doubleToLongBits (except all NaN values are collapsed to a single "canonical" NaN value).

double n = 171.30672219;
System.out.println(Double.doubleToLongBits(n));
System.out.println(Double.longBitsToDouble(Double.doubleToLongBits(n)));