python - EOFError : Ran out of input 错误

Question

当我运行下面的代码时，我收到此错误消息“EOFError: Ran out of input”这是什么意思？？怎么才能矫正？？以及如何在屏幕上输出记录的详细信息。

import pickle # this library is required to create binary files
class CarRecord:
    def __init__(self):
      self.VehicleID = " "          
      self.Registration = " "
      self.DateOfRegistration = " "
      self.EngineSize = 0           
      self.PurchasePrice = 0.00

ThisCar = CarRecord()
Car = [ThisCar for i in range(2)] # list of 2 car records

Car[0].VehicleID = "CD333"
Car[0].Registration = "17888"
Car[0].DateOfRegistration = "18/2/2017"
Car[0].EngineSize = 2500
Car[0].PurchasePrice = 22000.00

Car[1].VehicleID = "AB123"
Car[1].Registration = "16988"
Car[1].DateOfRegistration = "19/2/2017"
Car[1].EngineSize = 2500
Car[1].PurchasePrice = 20000.00

CarFile = open ('Cars.TXT', 'wb' ) # open file for binary write
for j in range (2): # loop for each array element
    pickle.dump (Car[j], CarFile) # write a whole record to the binary file
CarFile.close() # close file

CarFile = open ('Cars.TXT','rb') # open file for binary read
Car = [] # start with empty list
while True: #check for end of file
    Car.append(pickle.load(CarFile)) # append record from file to end of list
CarFile.close()

Answer 1

简短回答:最简单的解决方案是使用 pickle.dump() 将完整列表写入文件。没有必要在循环中一个一个地写入所有对象。 Pickle 专为您设计。

示例代码和替代解决方案:

下面是一个完整的示例。一些注意事项:

• 我已经稍微更新了您的 __init__ 函数，使初始化代码更简单、更短。
• 我还添加了一个 __repr__ 函数。这可用于将记录详细信息打印到屏幕上，这也是您要求的。 (请注意，您也可以实现 __str__ 函数，但我选择在本示例中实现 __repr__)。
• 此代码示例使用标准 Python 编码风格 (PEP-8)。
• 此代码使用上下文管理器打开文件。这样更安全，无需手动关闭文件。

如果您真的想手动编写对象，无论出于何种原因，有一些替代方法可以安全地进行。我将在这个代码示例之后解释它们:

import pickle


class CarRecord:

    def __init__(self, vehicle_id, registration, registration_date, engine_size, purchase_price):
        self.vehicle_id = vehicle_id
        self.registration = registration
        self.registration_date = registration_date
        self.engine_size = engine_size
        self.purchase_price = purchase_price

    def __repr__(self):
        return "CarRecord(%r, %r, %r, %r, %r)" % (self.vehicle_id, self.registration,
                                                  self.registration_date, self.engine_size,
                                                  self.purchase_price)


def main():
    cars = [
        CarRecord("CD333", "17888", "18/2/2017", 2500, 22000.00),
        CarRecord("AB123", "16988", "19/2/2017", 2500, 20000.00),
    ]

    # Write cars to file.
    with open('Cars.TXT', 'wb') as car_file:
        pickle.dump(cars, car_file)

    # Read cars from file.
    with open('Cars.TXT', 'rb') as car_file:
        cars = pickle.load(car_file)

    # Print cars.
    for car in cars:
        print(car)


if __name__ == '__main__':
    main()

输出:

CarRecord('CD333', '17888', '18/2/2017', 2500, 22000.0)
CarRecord('AB123', '16988', '19/2/2017', 2500, 20000.0)

您可以也可以循环执行，而不是立即转储列表。以下代码片段是“将汽车写入文件”和“从文件读取汽车”的替代实现。

备选方案 1:将对象数量写入文件

在文件的开头，写下汽车的数量。这可用于从文件中读取相同数量的汽车。

    # Write cars to file.
    with open('Cars.TXT', 'wb') as car_file:
        pickle.dump(len(cars), car_file)
        for car in cars:
            pickle.dump(car, car_file)

    # Read cars from file.
    with open('Cars.TXT', 'rb') as car_file:
        num_cars = pickle.load(car_file)
        cars = [pickle.load(car_file) for _ in range(num_cars)]

备选方案 2:使用“结束”标记

在文件末尾，写入一些可识别的值，例如None。读取此对象时可用于检测文件结尾。

    # Write cars to file.
    with open('Cars.TXT', 'wb') as car_file:
        for car in cars:
            pickle.dump(car, car_file)
        pickle.dump(None, car_file)

    # Read cars from file.
    with open('Cars.TXT', 'rb') as car_file:
        cars = []
        while True:
            car = pickle.load(car_file)
            if car is None:
                break
            cars.append(car)