python - 在python中将字符串压缩为数字

Question

我想将我的序列从 format(AAAABBCCdd) 转换为 (A4B2C2d2) 并且区分大小写。

这是我的代码，但它不返回最后一个字母的数字。如果您能帮我改正我的错误，我将不胜感激。

#[AAABBBCCCDDDDDD] -> [A3B3C3D]
def compressStToNum(A):
    Ans = [A[0]]
    count = 0
    for letter in A:
        if letter in Ans:
            count += 1
            
        else:
            Ans = Ans + [count]
            Ans = Ans + [letter]

            count = 1

        list_of_strings = [str(s) for s in Ans]
        joined_string = "".join(list_of_strings)

    print(joined_string)

print(compressStToNum("AAABBBBCCCSSS"))

Answer 1

这对我有用:

#[AAABBBCCCDDDDDD] -> [A3B3C3D5]
def compressStToNum(sequence):
    previous_letter = sequence[0]
    compressed_sequence = ''
    count = 1
    for letter in sequence[1:]+' ':
        if letter == previous_letter:
            count += 1
            continue
        
        compressed_sequence += previous_letter + str(count)
        previous_letter = letter
        count = 1
    return compressed_sequence
    

print(compressStToNum("AAABBBBCCCSSS"))