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python - python中列表字典的概率

转载 作者:行者123 更新时间:2023-12-05 09:04:32 26 4
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我有这个列表字典:

my_dict = {'Summer':['Summer','Summer','gone'],'gone':['forever'],'forever':['gone']}

我希望列表中每个单词的概率作为字典,在这种情况下,预期的字典是:

my_dict_probs = {'Summer':{'Summer':0.66,'gone':0.33}, 'gone':{'forever':1}, 'forever'{'Summer':1}

所以我试过这个:

prob_dict = {}
for k,v in my_dict.items():
prob_dict[k] = v/len(v)
prob_dict

我收到此错误:TypeError: unsupported operand type(s) for/: 'list' and 'int'。我想我应该计算每个唯一值,所以我的方法不起作用。拜托,你能帮帮我吗?

最佳答案

试试这个

my_dict = {'Summer':['Summer','Summer','gone'],'gone':['forever'],'forever':['gone']}
for v in my_dict:
my_dict[v]={j:round(my_dict[v].count(j)/len(my_dict[v]),2) for j in my_dict[v]}
print (my_dict)

关于python - python中列表字典的概率,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/68516113/

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