python - 断言一个数字是二进制的

Question

我正在做作业，遇到了一个问题。我不得不将二进制数字串接起来。假设我们加入了 (1, 3) - 1 是起始数字，3 表示我将使用另外 2 个数字(如果我加入了 (5, 4)，id 将使用 5、6、7 和 8)1 12 103 11结果 11011

def num_to_2(number):
    num2 = 0
    exp = 0
    while number >= 1:
        num2 += (number % 2) * (10 ** exp)
        number = number // 2
        exp += 1
    return num2


def num_lenght(number):
    if number == 0:
        return 0
    lenght = 0
    while number >= 1:
        number /= 10
        lenght += 1
    return lenght


def joined(start, count):
    result = 0
    end = start + count - 1
    for i in range(end, start - 1, -1):
        number = num_to_2(i)
        res_lenght = num_lenght(result)
        result += number * (10 ** res_lenght)
    return result


def main():
    assert joined(1, 3) == 0b11011
    assert joined(10, 4) == 0b1010101111001101
    assert joined(8, 5) == 0b10001001101010111100
    assert joined(99, 2) == 0b11000111100100
    assert joined(999, 3) == 0b111110011111111010001111101001
    assert joined(1111, 1) == 0b10001010111

函数正常工作，但它给我的结果没有 0b 前缀，我需要它来传递断言。我如何在那里添加它？还有:我不能使用字符串。

提前致谢!

编辑:我添加了其余的代码，这样更有意义

Answer 1

我已经解决了我的问题，我所要做的就是“手动”将伪二进制数转换为以 10 为基数的数字。这是我的代码:

def convert_to_2(number):
    num2 = 0
    exp = 0
    while number >= 1:
        num2 += (number % 2) * (10 ** exp)
        number = number // 2
        exp += 1
    return num2


def num_lenght(number):
    if number == 0:
        return 0
    lenght = 0
    while number >= 1:
        number /= 10
        lenght += 1
    return lenght


def joined(start, count):
    result = 0
    end = start + count - 1
    for i in range(end, start - 1, -1):
        number = convert_to_2(i)
        res_lenght = num_lenght(result)
        result += number * (10 ** res_lenght)
    result = convert_to_10(result)
    return result


def convert_to_10(number):
    num10 = 0
    exp = 0
    while number >= 1:
        num10 += (number % 10) * (2 ** exp)
        number = number // 10
        exp += 1
    return num10


def main():
    assert joined(1, 3) == 0b11011
    assert joined(10, 4) == 0b1010101111001101
    assert joined(8, 5) == 0b10001001101010111100
    assert joined(99, 2) == 0b11000111100100
    assert joined(999, 3) == 0b111110011111111010001111101001
    assert joined(1111, 1) == 0b10001010111


if __name__ == "__main__":
    main()

非常感谢你的帮助(: