javascript - 如何在 JavaScript 中使用 id 查找唯一值？

Question

如何在 JavaScript 中查找带有 id 的唯一值？现在我得到的只是值(value)。

我得到:-

[
  "Care One",
  "Care Two"
]

我需要:-

[
{
    "Source_ID": 1,
    "SourceName_CR": "Care One"
},
{
    "Source_ID": 2,
    "SourceName_CR": "Care Two"
}

]

我的代码:-

const body = [
{
            Field_ID: 1,
            FieldName_CR: "First Name",
            Source_ID: 1,
            SourceName_CR: "Care One"
        },
        {
            Field_ID: 2,
            FieldName_CR: "Last Name",
            Source_ID: 1,
            SourceName_CR: "Care One"
        }, {
            Field_ID: 3,
            FieldName_CR: "Phone",
            Source_ID: 2,
            SourceName_CR: "Care Two"
        },
        {
            Field_ID: 4,
            FieldName_CR: "Email",
            Source_ID: 2,
            SourceName_CR: "Care Two"
        },  ];

console.log([...new Set(body.map(item => item.SourceName_CR))]);

Answer 1

Set 在这里不起作用，因为您想要删除重复的对象 - 但对象不能以这种方式相互比较。只做 .map(item => item.SourceName_CR) 也没有意义，因为那样你只会得到字符串(例如 Care Two)而不是整个对象想要。

按要删除重复数据的源 ID 对源名称进行分组，然后将生成的对象的条目转换为所需的结构。

const body = [
{
    Field_ID: 1,
    FieldName_CR: "First Name",
    Source_ID: 1,
    SourceName_CR: "Care One"
},
{
    Field_ID: 2,
    FieldName_CR: "Last Name",
    Source_ID: 1,
    SourceName_CR: "Care One"
}, {
    Field_ID: 3,
    FieldName_CR: "Phone",
    Source_ID: 2,
    SourceName_CR: "Care Two"
},
{
    Field_ID: 4,
    FieldName_CR: "Email",
    Source_ID: 2,
    SourceName_CR: "Care Two"
},  ];
const namesBySourceID = Object.fromEntries(
  body.map(obj => [obj.Source_ID, obj.SourceName_CR])
);
const result = Object.entries(namesBySourceID)
  .map(([Source_ID, SourceName_CR]) => ({ Source_ID, SourceName_CR }));
console.log(result);