mule - 数据编织函数

Question

这是我的 JSON 请求，我想在 DataWeave 转换中从我的 JSON 负载中删除 dcsId 字段。

我该怎么做？

{
    "status": "ok",
    "statusCode": "11011",
    "statusDescription": "Service: Get Profile ; Market: US ; Locale:en-US ; SourceId:DCS; ApiUid: 644e1dd7-2a7f-18fb-b8ed-ed78c3f92c2b; Description: The get profile call was successful.",
    "details": {
        "dcsId": "rfggrg",
        "marketCode": "US",
        "languageCode": "en",
        "profile": {
            "base": {
                "username": "abc",
                "firstName": "xc",
                "middleName": "test",
                "lastName": "123",
                "shortName": "xc",
                "displayName": "D",
                "suffix": "T",
                "prefix": "E"
            }
        }
    }
}

Answer 1

为了避免payload中其他字段的映射，你可以试试这个——

%dw 1.0
%output application/json
---
(payload - 'details') ++ (payload.details - 'dcsId')

它首先获取 payload 中除细节之外的所有内容，然后通过排除 dcsId 添加细节。

喂!