java - 用于更新查询的 JPA @Query 注释(oracle sql 开发人员)——org.hibernate.exception.GenericJDBCException : could not execute query

Question

我有一个存储库文件共享相同的源代码和一个 Controller 类，通过它我为一个更新语句调用 @query 函数。我想将一列数据更新到我的 Oracle 数据库中，为此我编写了 JPA update @query 并将该函数定义到一个存储库文件中，因此从我的 Controller 类之一进行调用无法执行查询。

存储库文件

package com.sid.demo.repository;

import java.util.List;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.jpa.repository.Modifying;
import org.springframework.data.jpa.repository.Query;
import org.springframework.data.repository.query.Param;
import com.sid.demo.model.hindalco_model;

public interface update_password extends JpaRepository<hindalco_model,Integer> 
{   
    @Query(value="update USER_REGISTRATION set password = :password WHERE user_name = :user_name and email = :email",nativeQuery=true)
    List<String> findbyuser_update(@Param("password") String password,String user_name,String email);   
}

Controller 类

@RequestMapping(value="/update_password",method = RequestMethod.POST)
    public String update_password(@RequestParam String password)
    {
        //String rnumber_verified=randomNumber;
        //int random_otp_verified=Integer.parseInt(rnumber_verified);



        //System.out.println("update query string value = "+hindalco_user_login12);
        System.out.println("user_name outside try = "+user_name12);
        System.out.println("email outside try = "+password12);
        try
        {
            System.out.println("user_inside try = "+user_name12);
            System.out.println("email inside try = "+password12);

            update_password_repo.findbyuser_update(password,user_name12,password12);
            return "Entered password successfully updated"; 
        }
        catch(Exception e)
        {
            return"Iam sorry entered password did not match "+e;
        }

    }

模型类

package com.sid.demo.model;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;


@Entity
@Table(name="user_registration")
public class hindalco_model
{
    @GeneratedValue(strategy=GenerationType.AUTO)
    @Id
    @Column(name="user_id")
    private int user_id;

    @Column(name="user_name")
    private String user_name;

    @Column(name="email")
    private String email;

    @Column(name="password")
    private String password;

    public int getUser_id() {
        return user_id;
    }

    public void setUser_id(int user_id) {
        this.user_id = user_id;
    }

    public String getUser_name() {
        return user_name;
    }

    public void setUser_name(String user_name) {
        this.user_name = user_name;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }



    @Override
    public String toString() {
        return "hindalco_model [user_id=" + user_id + ", user_name=" + user_name + ", email=" + email + ", password="
                + password +"]";
    }



}

我只是想编写 JPA @query 来更新我的一个列数据，为此，我想将函数调用从 Controller 类传递到包含 @query 注释函数定义的存储库文件，该函数定义将自动转换为 hibernate 查询通过编译器，因此在 oracle 数据库中，数据将被更新。

Answer 1

@Transactional
@Modifying(clearAutomatically = true)
@Query(value="update USER_REGISTRATION set password = ?1 WHERE user_name = ?2 and email = ?3",nativeQuery=true)
void findbyuser_update(String password,String user_name,String email);   

@Modifying 注释用于增强@Query 注释，不仅可以执行 SELECT 查询，还可以执行 INSERT、UPDATE、DELETE，甚至 DDL 查询。