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Java ObjectMapper.readValue 将泛型类型转换为 LinkedHashMap

转载 作者:行者123 更新时间:2023-12-05 08:46:47 26 4
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    @Service
public class PokemonManager implements PokemonService {

private HttpResponse<String> getStringHttpResponseByUrl(final String url) {
HttpClient httpClient = HttpClient.newHttpClient();
HttpRequest request = HttpRequest.newBuilder()
.GET().header("accept", "application/json")
.uri(URI.create(url)).build();
HttpResponse<String> httpResponse = null;
try {
httpResponse = httpClient.send(request, HttpResponse.BodyHandlers.ofString());
} catch (IOException | InterruptedException e) {
e.printStackTrace();
}
return httpResponse;
}

private <T> T getObjectResponse(T t, String url) {
ObjectMapper objectMapper = new ObjectMapper();
try {
t = objectMapper.readValue(getStringHttpResponseByUrl(url).body(), new TypeReference<>() {
});
} catch (JsonProcessingException e) {
e.printStackTrace();
}

return t;
}

private List<Pokemon> getAllPokemonsAsList() {

final String POSTS_API_URL = "https://pokeapi.co/api/v2/pokemon?limit=10000";
PokeApiResponse pokeApiResponse = new PokeApiResponse();
pokeApiResponse = getObjectResponse(pokeApiResponse, POSTS_API_URL);
System.out.println(pokeApiResponse);
return pokeApiResponse.results;
}

@Override
public List<Pokemon> getAll() {
return getAllPokemonsAsList();
}

我有上面的代码。如果我不在“getObjectResponse”方法中使用泛型,代码就可以正常工作。但是,当我使用泛型时,“t”的类型变成了“LinkedHashMap”而不是“PokeApiResponse”,代码崩溃了。我该如何解决这个问题?

最佳答案

通常你会使用它:

objectMapper.readValue("yourJSONHere", PokeApiResponse.class);

如果你想要一个通用的 T 响应,也许这会起作用

private <T> T getGeneric(Class<T> clazz, String json) throws IOException {
return new ObjectMapper().readValue(json, clazz);
}

例子:

    Pokemon charmander = getGeneric(Pokemon.class, "{\n" +
" \"name\": \"charmander\"\n" +
"}");

关于Java ObjectMapper.readValue 将泛型类型转换为 LinkedHashMap,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/69028982/

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