javascript - 检查对象中的任何数组是否包含空值

Question

我有一个名为 newEntries 的对象，到目前为止它有 2 个条目:

(2) [{…}, {…}]
0: {name: "test", website: "", sector: "", house: ""}
1: {name: "", website: "", sector: "", house: ""}
length: 2
__proto__: Array(0)

可见，目前只填充了一个索引的一个字段。如果所有元素的所有字段都已填充，我需要返回 true，否则返回 false。

我如何在 javascript 中这样做？

Answer 1

使用 .every 和 .some 的组合对我们有用:-

const array1 = [
{name: "test", website: "fdf", sector: "fdf", house: "fdf"},
{name: "fds", website: "fsd", sector: "fds", house: "fsdf"}]

const array2 = [
{name: "test", website: "", sector: "fdf", house: "fdf"},
{name: "fds", website: "fsd", sector: "fds", house: "fsdf"}]


function checkArray(array){
  return array.every(item => 
    !Object.values(item).some(value => value === "")
  );
}

console.log(checkArray(array1));
console.log(checkArray(array2));