python - 如何在Django中制作删除按钮

Question

请帮助我了解如何制作删除按钮，它必须删除一个 Cat

class Cat(models.Model):
    class Meta():
        db_table = "cat"

    paw = models.IntegerField(default=4)
    name = models.CharField(max_length=30, null=False, default='Cat')
    age = models.IntegerField(default=False, null=False)
    species = models.CharField(max_length=50, blank=True)
    hairiness = models.IntegerField(default=False, null=False)

    def __str__(self):
        return self.name

这是我的views.py，希望对您有所帮助。 (这是我星期一工作面试的需要)

from django.shortcuts import render, get_object_or_404
from .models import Cat
from .forms import CatForm
from django.shortcuts import redirect

def home(request):
    template = "base.html"
    queryset = Cat.objects.all()
    context = {
        "object_list": queryset
    }
    return render(request, template, context)

def new_cat(request):
    if request.method == "POST":
        form = CatForm(request.POST)
        if form.is_valid():
            cat = form.save(commit=False)
            cat.save()
            return redirect('/', pk=cat.pk)
    else:
        form = CatForm()
    return render(request, 'new_cat.html', {'form': form})

def cat_edit(request, pk):
    cat = get_object_or_404(Cat, pk=pk)
    if request.method == "POST":
        form = CatForm(request.POST, instance=cat)
        if form.is_valid():
            cat = form.save(commit=False)
            cat.save()
            return redirect('/', pk=cat.pk)
    else:
        form = CatForm(instance=cat)
    return render(request, 'new_cat.html', {'form': form})

站点是 asc 以添加更多详细信息，但我只是不知道还能添加什么。

from django.conf.urls import url
from . import views


urlpatterns = [
    url(r'^$', views.home, name='home'),
    url(r'^new/$', views.new_cat, name='new_cat'),
    url(r'^edit/(?P<pk>[0-9]+)/$', views.cat_edit, name='cat_edit'),
]

Answer 1

首先，您应该创建一个 cat_delete View ，它应该看起来像这样:

def cat_delete(request, pk):
    cat = get_object_or_404(Cat, pk=pk)  # Get your current cat

    if request.method == 'POST':         # If method is POST,
        cat.delete()                     # delete the cat.
        return redirect('/')             # Finally, redirect to the homepage.

    return render(request, 'template_name.html', {'cat': cat})
    # If method is not POST, render the default template.
    # *Note*: Replace 'template_name.html' with your corresponding template name.

然后，您应该将此 View 映射到您的 urls.py 中:

from django.conf.urls import url
from . import views

app_name = 'cats'
# Note that app_name is added here!
# It is used as a namespace in order to reverse your urls better.
# See usage in template.

urlpatterns = [
    # ...
    url(r'^delete/(?P<pk>[0-9]+)/$', views.cat_delete, name='cat_delete')
]

在您的模板中，您应该创建一个带有删除按钮 的表单，它只会向删除 View 发送一个POST 请求:

<form action="{% url 'cats:cat_delete' cat.id %}" method="post">
    {% csrf_token %}
    <input type="submit" value="Delete cat">
</form>

仔细观察表单的操作:

{% url 'cats:cat_delete' cat.id %}

我在这里使用 app_name来自 urls.py我之前添加的是为了按名称而不是路径解析您的网址。现在cats:cat_delete将评估为 cats/delete/<pk> .当然你通过了cat.id .

这应该可以解决删除 Cat 实例的问题模型。希望我有所帮助。