php - Symfony 进程组件中的多个命令

Question

我正在尝试使用 Symfony 进程组件执行多个命令，但第二个命令未被处理。我做错了什么？

        $process = new Process('sshpass -p password ssh user@host');
        $process->run();
        if (!$process->isSuccessful()) {
            throw new ProcessFailedException($process);
        }
        echo $process->getOutput();

        $process1 = new Process("sudo reboot -f");
        $process1->run();
        if (!$process1->isSuccessful()) {
            throw new ProcessFailedException($process1);
        }
        echo $process1->getOutput();

Answer 1

这就是使用 symfony process 运行多个命令的方式

$process = new Process('sshpass -p password ssh user@host');
$process->run();                            //Run the command (whole process)

if (!$process->isSuccessful()) {            //Executes after the command finishes
    throw new ProcessFailedException($process);
}

echo $process->getOutput();                 //Output the result (optional)

$process->setCommandLine('sudo reboot -f'); //Set a new Command to the current process
$process->run();                            //Run this process again

if (!$process->isSuccessful()) {            //Executes after the command finishes
    throw new ProcessFailedException($process);
}

echo $process->getOutput();                 //Next output (also optional)

如评论中所述，setCommandLine 方法已在 symfony 5 中删除。因此此解决方案仅适用于 symfony <= 4.4(最新的 symfony 4 版本)