laravel - 如何在 Laravel 中重用 phpunit 测试方法

Question

我有 2 个测试类，所有测试都运行良好。但问题是我不知道如何重用其他测试类方法。很抱歉，我是 Phpunit 的新手，我已经在搜索，但找不到解决方案。

class A_Test {

    public function create_something_1()
    {
        $this->visit('/a/create')
             ->type('Name','name')
             ->press('Submit')
             ->seeInDatabase('something_1', ['name' => 'Name']);
        $data = \App\Models\Something1::first();

        return $data;
    }

}


class B_Test {

    public function create_something_2()
    {

        // The problem is here, I result of new A_Test always null
        $a = (new A_Test)->create_something_1();

        $this->visit('/b/create')
             ->select($a->id, 'something_1')
             ->type('New Name','name')
             ->press('Submit')
             ->seeInDatabase('something_2', ['name' => 'New Name']);

    }

}

为了让 B_Test 正常工作，我总是像这样复制 A_Test 类中的方法

class B_Test {

    public function create_something_1()
    {
        $this->visit('/a/create')
             ->type('Name','name')
             ->press('Submit')
             ->seeInDatabase('something_1', ['name' => 'Name']);
        $data = \App\Models\Something1::first();

        return $data;
    }

    public function create_something_2()
    {
        // This is work
        $a = $this->create_something_1();

        $this->visit('/b/create')
             ->select($a->id, 'something_1')
             ->type('New Name','name')
             ->press('Submit')
             ->seeInDatabase('something_2', ['name' => 'New Name']);

    }

}

Answer 1

在您的 tests/TestCase.php 文件中，您可以这样做:

class TestCase extends Illuminate\Foundation\Testing\TestCase
{
    ....
    protected function create_something_resusable()
    {
        $this->visit('/a/create')
             ->type('Name','name')
             ->press('Submit')
             ->seeInDatabase('something_1', ['name' => 'Name']);
        $data = \App\Models\Something1::first();

        return $data;
    }
    ....
}

然后所有的测试都可以调用$this->create_something_resusable()，但记得在所有测试中扩展TestCase类。