python - 如何控制 django REST 框架返回的 JSON 的顺序？

Question

我想了解要编写什么级别的代码来控制 django 序列化程序返回的顺序。必须在模板级别、模型级别或序列化程序级别完成。什么决定了任何序列化程序返回的 JSON 中字段的顺序？在我的示例中，考虑这些序列化程序类:

class FilterURLSerializer(serializers.Serializer):
    active = serializers.CharField(read_only=True)
    inactive = serializers.CharField(read_only=True)


class FacetedFilterOptionsSerializer(serializers.Serializer):
    name = serializers.CharField(read_only=True)
    slug = serializers.CharField(read_only=True)
    count = serializers.IntegerField(read_only=True)
    active = serializers.BooleanField(read_only=True)
    urls = FilterURLSerializer(read_only=True)


class FacetedFilterSerializer(serializers.Serializer):
    name = serializers.CharField(read_only=True)
    slug = serializers.CharField(read_only=True)
    options = FacetedFilterOptionsSerializer(source='options')

以及返回的 JSON 数据:

{'name': u'Skill level', 'slug': u'skill', 'options': [{'name': u"I'm Learning", 'slug': u'beginner', 'count': 0, 'active': False, 'urls': {'active': u'/en-US/search?skill=beginner', 'inactive': u'/en-US/search'}}, {'name': u"I'm an Expert", 'slug': u'advanced', 'count': 0, 'active': False, 'urls': {'active': u'/en-US/search?skill=advanced', 'inactive': u'/en-US/search'}}, {'name': u'Intermediate', 'slug': u'intermediate', 'count': 0, 'active': False, 'urls': {'active': u'/en-US/search?skill=intermediate', 'inactive': u'/en-US/search'}}]}

我想知道是什么决定了 JSON 中这些字段的顺序，我该如何更改它？

Answer 1

如果您希望对字段名称进行排序，您可以尝试以下操作:

myList = list(yourmodel.objects.values('filed1','field2').filter(someid=i).orderby('column'))