java - Hibernate envers - 嵌套对象的加载历史

Question

我有一个实体，它有一些列表，看起来像这样:

@Entity
@Table(name = "HOME")
@Audited
public class House {

    @Id
    private Integer id;

    @Version
    @Column(name = "UPDATE_DATE", nullable = false)
    private Date updateDate;

    @Column(name = "DESCRIPTION", nullable = false)
    private String description;

    @Cascade(CascadeType.ALL)
    @OneToMany(fetch = FetchType.LAZY, mappedBy = "home", orphanRemoval = true)
    private Set<Room> rooms;

    [...]

}

同时假设 Room 实体看起来像这样:

@Entity
@Table(name = "ROOM")
@Audited
public class Room {

    @Id
    private Integer id;

    @Version
    @Column(name = "UPDATE_DATE", nullable = false)
    private Date updateDate;

    @Column(name = "NAME", nullable = false)
    private String name;

    @Cascade(CascadeType.ALL)
    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name="HOUSE", nullable=false)
    private House house;

    [...]

}

如您所见，房间是通过级联保存的。让我们进入我的问题的核心......

先决条件:

房子对象中的当前数据:

House:
    description: "red house"
    rooms: [room1, room2]

审计表中的当前数据:

--- HOUSE_A ---
| REV | REVTYPE | ID | UPDATE_DATE     | DESCRIPTION |
+-----+---------+----+-----------------+-------------+
| 111 | 0       | 10 | 2015-08-3 12:00 | red house   |

--- ROOM_A ---
| REV | REVTYPE | ID  | UPDATE_DATE     | NAME  | HOUSE |
| 111 | 0       | 100 | 2015-08-3 12:00 | room1 | 10    |
| 111 | 0       | 110 | 2015-08-3 12:00 | room2 | 10    |

用户步骤:

使用这些数据更新房屋对象(更改房屋描述):

House:
    description: "blue house"
    rooms: [room1, room2]

执行此操作后，审核表将如下所示:

--- HOUSE_A ---
| REV | REVTYPE | ID | UPDATE_DATE     | DESCRIPTION  |
+-----+---------+----+-----------------+--------------+
| 111 | 0       | 10 | 2015-08-3 12:00 | red house    |
| 112 | 1       | 10 | 2015-08-3 12:30 | blue house   |

--- ROOM_A ---
| REV | REVTYPE | ID  | UPDATE_DATE     | NAME  | HOUSE |
| 111 | 0       | 100 | 2015-08-3 12:00 | room1 | 10    |
| 111 | 0       | 110 | 2015-08-3 12:00 | room2 | 10    |

使用这些数据更新房屋对象(不更改房屋对象并添加一个房间):

House:
    description: "blue house"
    rooms: [room1, room2, room3]

执行此操作后，审核表将如下所示:

--- HOUSE_A ---
| REV | REVTYPE | ID | UPDATE_DATE     | DESCRIPTION  |
+-----+---------+----+-----------------+--------------+
| 111 | 0       | 10 | 2015-08-3 12:00 | red house    |
| 112 | 1       | 10 | 2015-08-3 12:30 | blue house   |

--- ROOM_A ---
| REV | REVTYPE | ID  | UPDATE_DATE     | NAME  | HOUSE |
| 111 | 0       | 100 | 2015-08-3 12:00 | room1 | 10    |
| 111 | 0       | 110 | 2015-08-3 12:00 | room2 | 10    |
| 113 | 0       | 120 | 2015-08-3 12:40 | room3 | 10    |

加载经审计的房屋数据:

--- current result ---
HOUSE_A(last_rev) -> HOUSE_A(112) -> 'blue house' with room1 and room2

--- expected result ---
HOUSE_A(last_rev) -> HOUSE_A(113) -> 'blue house' with room1, room2 and room3

问题来了...

house 的最高修订版是 112，但我完成的最后一个操作已保存为修订版 113(rev 条目尚未添加到 HOUSE_A，因为 house 对象没有更改)。我知道 envers 会加载修订版较少或相等的房屋对象的所有数据。在这种情况下，不会加载最后一个操作。问题是 - 加载这些类型操作(主要对象未更新)的唯一方法是在保存之前更新主要对象(房屋)的最后更新日期，以便将新条目添加到 HOUSE_A 中，修订版与 ROOM_A 中的相同？

在这个“解决方法”之后，审计的表将如下所示......

--- HOUSE_A ---
| REV | REVTYPE | ID | UPDATE_DATE      | DESCRIPTION  |
+-----+---------+----+------------------+--------------+
| 111 | 0       | 10 | 2015-08-30 12:00 | red house    |
| 112 | 1       | 10 | 2015-08-30 12:30 | blue house   |
| 113 | 1       | 10 | 2015-08-30 12:40 | blue house   |

--- ROOM_A ---
| REV | REVTYPE | ID  | UPDATE_DATE      | NAME  | HOUSE |
+-----+---------+-----+------------------+-------+-------+
| 111 | 0       | 100 | 2015-08-30 12:00 | room1 | 10    |
| 111 | 0       | 110 | 2015-08-30 12:00 | room2 | 10    |
| 113 | 0       | 120 | 2015-08-30 12:40 | room3 | 10    |

Answer 1

您没有提到您正在使用的 Envers 版本，但是在 Envers 5.x 中有一个默认启用的配置属性应该触发这个确切的功能:

org.hibernate.envers.revision_on_collection_change=true

由于 Room 拥有与 Home 的关系，启用此配置应该会导致 Envers 在 时记录 Home 的修订更改>Room 集合已修改。