pandas - 为什么 set_titles 不生成标题(Seaborn 和 Factorplot)？

Question

这是我正在使用的代码。这是一个可以复制和粘贴的独立代码。

import pandas as pd
import numpy as np
import seaborn as sns
import matplotlib.pyplot as plt



### Load the Titanic dataset
titanic = sns.load_dataset("titanic")

### Divide the data by sex; male and female

male = titanic[titanic.sex == 'male']
female = titanic[titanic.sex == 'female']




### Now use groupby to group by fare//5 and then create a column with the  survival rate for each group

male_chart= male.groupby([male.fare // 5]).survived.mean().reset_index()
female_chart= female.groupby([female.fare // 5]).survived.mean().reset_index()



#Plot male_chart
sns.set(style="whitegrid")
g = sns.factorplot(x='fare', y= 'survived',  data=male_chart,
               size=6, aspect =3 ,kind="bar", palette="muted")

g.despine(left=True)
g.set_ylabels("Survival Probability")
g.set_xlabels('Fare *5')
g.set_titles('Males')   # set_title doesn't produce "Males" on the chart itself



#sns.plt.title('Males')   #This code seems to work but not sure why it does. 


#plot: female_chart

h= sns.factorplot(x='fare', y= 'survived',  data=female_chart,
               size=6, aspect =3 ,kind="bar", palette="muted")
h.despine(left=True)
h.set_ylabels("survival probability")
h.set_xlabels('fare *5')
h.set_titles('Females')  #Once again doesn't work.
#sns.plt.title('Females')  #but this works
plt.show()

我在运行“set_titles”行时没有收到任何错误，但它没有在图表本身上生成标题。我如何错误地使用 set_title？感谢你的帮助。

Answer 1

set_titles ("NName of plot") 仅适用于 FacetGrid，其中有 x 列或 y 行。

(例如)

facet_grid = sns.relplot(data=data, x = "X", y = "Y", col = "Split"). set_titles("Works fine")

如果您的图不是FacetGrid 并且您使用set_titles 它不会显示标题

例如

不会起作用

plt.figure(figsize=(20,6))  
sns.displot(df["GPA"],kind='kde').set_titles("Distribution of Data")

工作正常

plt.figure(figsize=(20,6)) # works fine
sns.displot(df["GPA"],kind='kde').set(title='Title of Plot')

https://seaborn.pydata.org/generated/seaborn.FacetGrid.set_titles.html