bash - 如何在 bash 中迭代多行变量？

Question

给定

# this is programmatically generated... hard-coded here for this example
commands="\nthing1@this is thing 1!\nthing2@this is thing 2!"

while read -r line; do
  cmd=$(printf "$line" | cut -d'@' -f1 | tr -d '\n')
  desc=$(printf "$line" | cut -d'@' -f2 | tr -d '\n')

  printf '  %-20s %s\n' "$cmd" "$desc"
done <<< "$commands"

我希望能输出

  thing1        this is thing1!
  thing2        this is thing2!

相反我得到

  thing1thing2        this is thing1!this is thing2!

我做错了什么？

我想在换行符上读取，这样我就可以在@ 和printf 上相应地cut。

Answer 1

#!/bin/bash

input="\nthing1@this is thing 1!\nthing2@this is thing 2!"

# echo replaces '\n's with real new-lines
# readarray -t loads the multiline string into an array
readarray -t array <<< $(echo -e "${input}")

# loop it
for command in "${array[@]}"; do
    echo "${command}"
done