gpt4 book ai didi

spring - 创建新实体加关联不起作用

转载 作者:行者123 更新时间:2023-12-05 07:39:03 27 4
gpt4 key购买 nike

我有两个实体 AppUserUserGroup。他们有一个 @ManyToMany 关系。

我目前正在尝试为现有用户创建关联一个新组,如下所示:

POST http://localhost:8080/groups

{
"name": "Group 1",
"users": ["http://localhost:8080/users/1"]
}

问题是只有组被创建 - 但没有与列出的用户关联 - 服务器仍然响应 201 Created?!

这是两个存储库:

@RepositoryRestResource(collectionResourceRel = "users", path = "users")
public interface AppUserRepository extends JpaRepository<AppUser, Long> {
AppUser findByUsername(@Param("username") String username);
}

@RepositoryRestResource(collectionResourceRel = "groups", path = "groups")
public interface UserGroupRepository extends JpaRepository<UserGroup, Long> {
List<UserGroup> findByName(@Param("name") String name);
}

下面你可以看到关系是如何定义的:

应用用户.java

@Column(name="user_group_id")
@ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinTable(name = "app_user__user_group",
joinColumns = {
@JoinColumn(name = "app_user_id", nullable = false, updatable = false) },
inverseJoinColumns = {
@JoinColumn(name = "user_group_id", nullable = false, updatable = false)})
private Set<UserGroup> groups;

用户组.java

@Column(name = "app_user_id")
@ManyToMany(fetch = FetchType.LAZY, mappedBy = "groups")
private Set<AppUser> users;

注意:

如果我只传递一个字符串,而不是 users 的列表:

POST http://localhost:8080/groups

{
"name": "Group 1",
"users": "http://localhost:8080/users/1"
}

我得到的是:

{
"cause": {
"cause": null,
"message": "Cannot deserialize instance of java.util.Set out of VALUE_STRING token at [Source: (org.apache.catalina.connector.CoyoteInputStream); line: 7, column: 12] (through reference chain: mahlzeit.api.hibernate.model.UserGroup["users"])"
},
"message": "JSON parse error: Cannot deserialize instance of java.util.Set out of VALUE_STRING token; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of java.util.Set out of VALUE_STRING token at [Source: (org.apache.catalina.connector.CoyoteInputStream); line: 7, column: 12] (through reference chain: mahlzeit.api.hibernate.model.UserGroup["users"])"
}

最佳答案

尝试

@Column(name = "app_user_id")
@ManyToMany(fetch = FetchType.LAZY, mappedBy = "groups",cascade = CascadeType.ALL)
private Set<AppUser> users;

最终通过用户列表

{
"name": "Group 1",
"users": ["http://localhost:8080/users/1"]
}

对于 Cannot deserialize instance of java.util.Set 错误它需要一个用户列表而不是单个用户的实例

关于spring - 创建新实体加关联不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47376620/

27 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com