batch-file - 如何使用批处理脚本替换文件中的两行文本

Question

我需要替换文本文件中的两行字符串。我写了一个替换一个字符串的脚本:

@echo off
setlocal enabledelayedexpansion

rem file name
Set infile=file.txt

rem what to find
Set find=123

rem value to replace
Set replace=321

@echo off
setlocal enabledelayedexpansion
set COUNT=0
for /F "tokens=* delims=," %%n in (!infile!) do (
set LINE=%%n
set TMPR=!LINE:%find%=%replace%!
Echo !TMPR!>>tmp.txt
)
move tmp.txt %infile%
pause

如何修改它一次替换2行？我的意思是“查找”到“替换”，“查找 2”到“替换 2”？

Answer 1

在您的set TMPR=... 之后，添加set TMPR=!TMPR:%find2%=%replace2%!:

@echo off
setlocal enabledelayedexpansion
del tmp.txt
rem file name
Set infile=file.txt

rem what to find
Set find=abc
set find2=def

rem value to replace
Set replace=123
set replace2=456

for /F "tokens=* delims=," %%n in (!infile!) do (
set LINE=%%n
set TMPR=!LINE:%find%=%replace%!
set TMPR=!TMPR:%find2%=%replace2%!
Echo !TMPR!>>tmp.txt
)
type tmp.txt

文件.txt:

aaa
abc
bbb
def
ccc
xxxabcyyy
uuudefvvv
nnnabcdefmmm

输出:

aaa
123
bbb
456
ccc
xxx123yyy
uuu456vvv
nnn123456mmm