php - 如何在 Symfony 4 中记录登录失败？

Question

我的问题

我应该返回哪种不会更改默认响应的响应？或者是否有更好的方法将记录器附加到登录失败/badcredentialsexception？

详情

我找到了这篇文章 here其中声明您可以(在 Symfony 2.4 中)像这样自定义身份验证失败或成功:

use Symfony\Component\Security\Core\Exception\AuthenticationException;
use Symfony\Component\Security\Http\Authentication\AuthenticationFailureHandlerInterface;
use Symfony\Component\Security\Http\Authentication\AuthenticationSuccessHandlerInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;

class CustomTimeAuthenticator extends TimeAuthenticator implements AuthenticationFailureHandlerInterface, AuthenticationSuccessHandlerInterface
{
    public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
    {
        error_log('You are out!');
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token)
    {
        error_log(sprintf('Yep, you are in "%s"!', $token->getUsername()));
    }
}

它还指出

...you can also bypass the default behavior altogether by returning a Response instance:

public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
{
    if ($exception->getCode()) {
        return new Response('Not the right time to log in, come back later.');
    }
}

不幸的是，它似乎出现在 Symfony 4 中 you have to return a Response (与上面的 2.4 代码不同)所以我的代码是:

use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Security\Http\Authentication\AuthenticationFailureHandlerInterface;
use Symfony\Component\Security\Core\Exception\AuthenticationException;
use Symfony\Component\Security\Core\Authentication\Token\Storage\TokenStorageInterface;
use Psr\Log\LoggerInterface;

class LoginFailureLogger implements AuthenticationFailureHandlerInterface
{
    private $logger;
    private $security;

    public function __construct(TokenStorageInterface $security, LoggerInterface $logger)
    {
        $this->logger = $logger;
        $this->security = $security;
    }

    public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
    {
        $user = $exception->getToken()->getUser();

        $this->logger->notice('Failed to login user: "'. $user. '"".  Reason: '. $exception->getMessage());
    }
}

但是当页面运行时我得到:

Authentication Failure Handler did not return a Response.

Answer 1

您应该重定向到登录页面，因为这是默认行为。请根据您的具体要求进行修改。

use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\HttpFoundation\Session\Flash\FlashBagInterface;
...

private $flashBag;
private $logger;
private $security;

public function __construct(TokenStorageInterface $security, LoggerInterface $logger, FlashBagInterface $flashBag)
{
    $this->logger = $logger;
    $this->security = $security;
    $this->flashBag = $flashBag;
}

public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
{
    $user = $exception->getToken()->getUser();

    $this->logger->notice('Failed to login user: "'. $user. '"".  Reason: '. $exception->getMessage());

    $this->flashBag()->add('notice', 'Failed to login.');

    return new RedirectResponse('/login');
}

编辑:添加了即显消息