php - 如何查询员工详细信息并关联他们的绩效指标？

Question

我正在获取所有已批准但未存档的员工的 ID、名字和姓氏。然后我循环这些结果并使用 id 查询其他表以收集一些计数数据。

我尝试了下面的代码，但没有得到预期的输出。

$queryEmp = "
    SELECT id, firstname, lastname
    FROM tbl_employee as e
    WHERE is_archive=0 and is_approved=1
";
$getQuery= $this->db->query($queryEmp);
$result= $getQuery->result();
foreach ($result as $key=> $value) {
    //echo "<pre>";
    print_r($value);

    $day = "MONTH(date_of_created) = DATE(CURRENT_DATE())";
    $group = "f_id IN (SELECT MAX(f_id) FROM tbl_fileStatus GROUP BY f_bankid)";
    $condiion = "and ba.createdby='" . $value->id . "' and " . $day ." and " . $group;
    $query2 = "
        select
            (SELECT COUNT(c_id)
             FROM tbl_lead
             WHERE leadstatus='1' AND ".$day.") as confirmCount,

            (SELECT COUNT(f_id)
             FROM tbl_fileStatus as fs
             join tbl_bankdata as ba on ba.bank_id=fs.f_bankid
             WHERE fs.f_filestatus=1 " . $condiion . ") as disbursed,

            (SELECT COUNT(f_id)
             FROM tbl_fileStatus as fs
             join tbl_bankdata as ba on ba.bank_id=fs.f_bankid
             WHERE fs.f_filestatus=2 ".$condiion.") as filesubmit
    ";
    # code...
    $getQuery2= $this->db->query($query2);
    $result2[]=$getQuery2->result();
}
echo "<pre>";
print_r(result2);

$result 看起来像这样:

Array (
    [0] => stdClass Object (
        [id] => 1
        [firstname] => xyz
        [lastname] => xyz
    )
    ...
)

第二个查询输出:

Array (
    [0] => Array (
        [0] => stdClass Object (
            [fallowCall] => 0
            [confirmCount] => 0
            [disbursed] => 0
            [filesubmit] => 0
        )
    )
    ...
)

如何生成将各个员工与其绩效指标相关联的正确结果？无论是这种结构:

Array (
    [0] => stdClass Object (
        [id] => 1
        [firstname] => xyz
        [lastname] => xyz
        [somename] => (
            [fallowCall] => 0
            [confirmCount] => 0
            [disbursed] => 0
            [filesubmit] => 0
        )
    )
    ...
)

或者这个结构:

Array (
    [0] => stdClass Object (
        [id] => 1
        [firstname] => xyz
        [lastname] => xyz
        [fallowCall] => 0
        [confirmCount] => 0
        [disbursed] => 0
        [filesubmit] => 0
    )
    ...
)

我在这里添加了我的表结构和一些示例数据:https://www.db-fiddle.com/f/8MoWmKPuzTrrC3DQJsiX35/0

这里有一些注释

1) createdby是表tbl_employee的id>

2)bank表中的lead_id为表tbl_lead的c_id

3) tbl_fileStatus中的f_bankid为表tbl_bankdata的bank_id

Answer 1

实际上不需要创建额外的深度/复杂性来保存计数数据。此外，通过使用 LEFT JOIN 的组合来连接相关表并应用所需的条件规则，您只需访问数据库一次即可获得所需的结果。毫无疑问，这将为您的应用程序提供卓越的效率。 LEFT JOIN 使用起来很重要，这样计数可以为零，而不会将员工排除在结果集中。

此外，我应该指出，您尝试的查询错误地将 MONTH() 值与 DATE() 值进行了比较——这永远不会有好的结果. :) 事实上，为了确保您的 sql 准确地将当前月份与当前年份分开，您还需要检查 YEAR 值。

我推荐的sql:

SELECT
    employees.id,
    employees.firstname,
    employees.lastname,
    COUNT(DISTINCT leads.c_id) AS leadsThisMonth,
    SUM(IF(fileStatus.f_filestatus = 1, 1, 0)) AS disbursedThisMonth,
    SUM(IF(fileStatus.f_filestatus = 2, 1, 0)) AS filesubmitThisMonth
FROM tbl_employee AS employees

LEFT JOIN tbl_lead AS leads
    ON employees.id = leads.createdby
        AND leadstatus = 1 
        AND MONTH(leads.date_of_created) = MONTH(CURRENT_DATE())
        AND YEAR(leads.date_of_created) = YEAR(CURRENT_DATE())                                                 

LEFT JOIN tbl_bankdata AS bankData
    ON employees.id = bankData.createdby

LEFT JOIN tbl_fileStatus AS fileStatus
    ON bankData.bank_id = fileStatus.f_bankid
        AND MONTH(fileStatus.date_of_created) = MONTH(CURRENT_DATE())
        AND YEAR(fileStatus.date_of_created) = YEAR(CURRENT_DATE())
        AND fileStatus.f_id = (
                SELECT MAX(subFileStatus.f_id)
                FROM tbl_fileStatus AS subFileStatus
                WHERE subFileStatus.f_bankid = bankData.bank_id
                GROUP BY subFileStatus.f_bankid
            )

WHERE employees.is_archive = 0
    AND employees.is_approved = 1

GROUP BY employees.id, employees.firstname, employees.lastname

SUM(IF()) 表达式是一种用于执行“条件计数”的技术。 “聚合数据”是通过使用 GROUP BY 形成的，并且有专门的“aggregate functions”必须用于从这些集群/非平面数据集合创建线性/平面数据。 fileStatus 数据由于 GROUP BY 调用而有效地堆积在自身上。如果调用了 COUNT(fileStatus.f_filestatus)，它将计算集群中的所有行。由于您希望区分 f_filestatus = 1 和 f_filestatus = 2，因此使用了 IF() 语句。这与 COUNT() 做同样的事情(每次符合条件的出现加 1)，但它与 COUNT() 的不同之处在于它不计算特定行(在集群范围内)除非 IF() 表达式被满足。 Another example .

这是一个 db fiddle 演示，对您提供的示例数据进行了一些调整:https://www.db-fiddle.com/f/8MoWmKPuzTrrC3DQJsiX35/4 (结果集只会是“好”，而当前是今年 6 月。)

将上述字符串保存为$sql后，您可以简单地执行它并像这样遍历对象数组:

foreach ($this->db->query($sql)->result() as $object) {
    // these are the properties available in each object
    // $object->id
    // $object->firstname
    // $object->lastname
    // $object->leadsThisMonth
    // $object->disbursedThisMonth
    // $object->filesubmitThisMonth
}