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我当前的问题是我有一个运行余额,其中一个值低于另一个运行余额需要重置。但不仅要重置,还要用另一个值作为起始值,重新开始平衡。
下面是包含数据的表格:
+-------------+--------+---------------------+-------------------+--------------+-------------+
| Tran_DateSK | Amount | Running_AccountFees | Overlimit_Balance | Restart_Calc | Actual_Calc |
+-------------+--------+---------------------+-------------------+--------------+-------------+
| 20200217 | 39 | 39 | 3867.76 | 0 | 39 |
| 20200217 | 50 | 89 | 3867.76 | 0 | 89 |
| 20200316 | 39 | 128 | 4735.52 | 0 | 128 |
| 20200316 | 50 | 178 | 4735.52 | 0 | 178 |
| 20200324 | 50 | 228 | 2685.52 | 0 | 228 |
| 20200330 | 50 | 278 | 49.52 | 1 | 49.52 |
| 20200415 | 39 | 317 | 49.52 | 1 | 49.52 |
| 20200515 | 39 | 356 | 3917.28 | 0 | 88.52 |
| 20200515 | 50 | 406 | 3917.28 | 0 | 138.52 |
| 20200519 | 50 | 456 | 3467.28 | 0 | 188.52 |
| 20200604 | 50 | 506 | 3017.28 | 0 | 238.52 |
| 20200609 | 50 | 556 | 2167.28 | 0 | 288.52 |
| 20200611 | 50 | 606 | 49.28 | 1 | 49.28 |
| 20200615 | 39 | 645 | 3917.04 | 0 | 88.28 |
| 20200615 | 50 | 695 | 3917.04 | 0 | 138.28 |
| 20200616 | 50 | 745 | 3017.04 | 0 | 188.28 |
| 20200616 | 50 | 795 | 3017.04 | 0 | 238.28 |
| 20200619 | 50 | 845 | 2567.04 | 0 | 288.28 |
| 20200624 | 50 | 895 | 47.04 | 1 | 47.04 |
| 20200715 | 39 | 934 | 47.04 | 1 | 47.04 |
+-------------+--------+---------------------+-------------------+--------------+-------------+
实际计算是期望的结果,而运行帐户费用是问题。
流水账户费用是“金额”的流水余额,overlimit_balance是测试。我们需要确保 running_accountfees 不大于超限,
如果是,则取超限值并通过再次添加金额重新开始计算。
产生这个的我的查询:
SELECT
[Transaction].ReportDateSK AS 'Tran_DateSK'
,[Transaction].AmountChange/100.00 AS 'Amount'
,SUM([Transaction].AmountChange/100.00)
OVER (PARTITION BY [Transaction].AccountSK
ORDER BY [Transaction].ReportDateSK
ROWS BETWEEN UNBOUNDED PRECEDING AND 0 PRECEDING) AS 'Running_AccountFees'
,[Summary].Overlimit_Balance AS 'Overlimit_Balance'
,CASE
WHEN SUM([Transaction].AmountChange/100.00)
OVER (PARTITION BY [Transaction].AccountSK
ORDER BY [Transaction].ReportDateSK
ROWS BETWEEN UNBOUNDED PRECEDING AND 0 PRECEDING) > [Summary].Overlimit_Balance
THEN 1
ELSE 0
END AS 'Restart_Calc'
,'' AS 'Actual_Calc'
FROM
Fact.[Transaction] [Transaction]
INNER JOIN Fact.AccountSummary [Summary] ON [Summary].DateSK = [Transaction].ReportDateSK
AND [Summary].AccountSK = [Transaction].AccountSK
AND [Summary].[Current] = 1
WHERE IsFeeTransaction = 1
AND [Transaction].AccountSK = 725
AND [Transaction].ReportDateSK BETWEEN 20200217 AND 20200730
最佳答案
意识到您问题中的数据是本质上是源数据,并且能够得出以下结果。它不是很漂亮,但它提供了正确的输出。在评论中解释了它是如何工作的:
declare @t table(Tran_DateSK int, Amount decimal(10,2), Running_AccountFees int, Overlimit_Balance decimal(10,2), Restart_Calc bit, Actual_Calc decimal(10,2));
insert into @t values(20200217,39,39,3867.76,0,39),(20200217,50,89,3867.76,0,89),(20200316,39,128,4735.52,0,128),(20200316,50,178,4735.52,0,178),(20200324,50,228,2685.52,0,228),(20200330,50,278,49.52,1,49.52),(20200415,39,317,49.52,1,49.52),(20200515,39,356,3917.28,0,88.52),(20200515,50,406,3917.28,0,138.52),(20200519,50,456,3467.28,0,188.52),(20200604,50,506,3017.28,0,238.52),(20200609,50,556,2167.28,0,288.52),(20200611,50,606,49.28,1,49.28),(20200615,39,645,3917.04,0,88.28),(20200615,50,695,3917.04,0,138.28),(20200616,50,745,3017.04,0,188.28),(20200616,50,795,3017.04,0,238.28),(20200619,50,845,2567.04,0,288.28),(20200624,50,895,47.04,1,47.04),(20200715,39,934,47.04,1,47.04);
with t as
(
select Tran_DateSK
,Amount
-- Check if the Running_AccountFees are over the Overlimit_Balance
,case when sum(Amount) over (order by Tran_DateSK,Amount,Overlimit_Balance rows unbounded preceding) > Overlimit_Balance
-- If so, check if the Running_AccountFees in the previous row were also over the Overlimit_Balance
then case when (sum(Amount) over (order by Tran_DateSK,Amount,Overlimit_Balance rows unbounded preceding) - Amount) > lag(Overlimit_Balance,1,0) over (order by Tran_DateSK,Amount,Overlimit_Balance)
then 0 -- and in those instances this means multiple Restart_Calcs in a row, so set the Amount to zero as we don't want to increase the fees when calculating the Actual_Calc
else Amount
end
else Amount
end as Amount_Adj
,sum(Amount) over (order by Tran_DateSK,Amount,Overlimit_Balance rows unbounded preceding) as Running_AccountFees
,lag(Overlimit_Balance,1,0) over (order by Tran_DateSK,Amount,Overlimit_Balance) as Prev_Overlimit_Balance
,Overlimit_Balance
,case when sum(Amount) over (order by Tran_DateSK,Amount,Overlimit_Balance rows unbounded preceding) > Overlimit_Balance
then 1
else 0
end as Restart_Calc
from @t
)
,b as
(
select *
,case when Running_AccountFees > Overlimit_Balance -- If this row is the first in a possible series of balance resets
and sum(Amount_Adj) over (order by Tran_DateSK,Amount,Overlimit_Balance rows between unbounded preceding and 1 preceding) <= Prev_Overlimit_Balance
then Overlimit_Balance -- Take the Overlimit_Balance and subtract the *Adjusted* Running_AccountFees
- sum(Amount_Adj) over (order by Tran_DateSK,Amount,Overlimit_Balance rows between unbounded preceding and 1 preceding)
- Amount_Adj
else 0
end as Reset_Bal
from t
)
select Tran_DateSK
,Amount
,Running_AccountFees
,Overlimit_Balance
,Restart_Calc
-- For each *Adjusted* Running_AccountFees, apply the most negative Reset_Bal value, as this will contain the entire amount that needs to be reset from the current *Adjusted* Running_AccountFees to get the correct Balance_Calc
,sum(Amount_Adj) over (order by Tran_DateSK,Amount,Overlimit_Balance rows unbounded preceding)
+ min(Reset_Bal) over (order by Tran_DateSK,Amount,Overlimit_Balance rows unbounded preceding)
as Balance_Calc
from b
order by Tran_DateSK;
+-------------+--------+---------------------+-------------------+--------------+--------------+
| Tran_DateSK | Amount | Running_AccountFees | Overlimit_Balance | Restart_Calc | Balance_Calc |
+-------------+--------+---------------------+-------------------+--------------+--------------+
| 20200217 | 39.00 | 39.00 | 3867.76 | 0 | 39.00 |
| 20200217 | 50.00 | 89.00 | 3867.76 | 0 | 89.00 |
| 20200316 | 39.00 | 128.00 | 4735.52 | 0 | 128.00 |
| 20200316 | 50.00 | 178.00 | 4735.52 | 0 | 178.00 |
| 20200324 | 50.00 | 228.00 | 2685.52 | 0 | 228.00 |
| 20200330 | 50.00 | 278.00 | 49.52 | 1 | 49.52 |
| 20200415 | 39.00 | 317.00 | 49.52 | 1 | 49.52 |
| 20200515 | 39.00 | 356.00 | 3917.28 | 0 | 88.52 |
| 20200515 | 50.00 | 406.00 | 3917.28 | 0 | 138.52 |
| 20200519 | 50.00 | 456.00 | 3467.28 | 0 | 188.52 |
| 20200604 | 50.00 | 506.00 | 3017.28 | 0 | 238.52 |
| 20200609 | 50.00 | 556.00 | 2167.28 | 0 | 288.52 |
| 20200611 | 50.00 | 606.00 | 49.28 | 1 | 49.28 |
| 20200615 | 39.00 | 645.00 | 3917.04 | 0 | 88.28 |
| 20200615 | 50.00 | 695.00 | 3917.04 | 0 | 138.28 |
| 20200616 | 50.00 | 745.00 | 3017.04 | 0 | 188.28 |
| 20200616 | 50.00 | 795.00 | 3017.04 | 0 | 238.28 |
| 20200619 | 50.00 | 845.00 | 2567.04 | 0 | 288.28 |
| 20200624 | 50.00 | 895.00 | 47.04 | 1 | 47.04 |
| 20200715 | 39.00 | 934.00 | 47.04 | 1 | 47.04 |
+-------------+--------+---------------------+-------------------+--------------+--------------+
关于sql-server - SQL Server 动态重置运行余额,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/63261425/
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