python - 回合制游戏的菜单

Question

我们的老师给我们布置了一项任务，让我们做一款回合制游戏。

这只包括 name.strip() 但这不会提示玩家输入唯一的名字:

def start():
   
   print("\nNew game started...Setting up Player 1's team...\n")
  
   for total_characters in range (1,4):
       name = input('Enter a unique name for unit #'+str(total_characters)+'==> ')
       if not name.strip():
           print('Cant be blank name,please provide a unique name')
           return start()
       else:
           role_selection()

def role_selection():
   for total_characters in range (1):
       role = input('Select unit #'+str(total_characters)+' type: (W)arrior, (T)anker, or Wi(Z)ard ==> ')                        
       total_characters+=1
       if role.upper() == 'W':
           pass             
       elif role.upper() == 'T':
           pass       
       elif role.upper() == 'Z':
           pass
       else:
           print("I don't understand what are you typing.")
           return role_selection()

Answer 1

有些事情没有意义:

• 你有两次完全相同的功能:

  def set_up(team_size)

  def set_up(名称)

• 你正在做:

    for total_units in range(team_size):
        [...]

        invalid = True

        [...]

        while invalid: # Infinite loop
            set_up() # What's this function ?

从上面代码的注释中可以看出，您从未将invalid设置为False，导致死循环。

注意:我的建议是，在继续编写复杂项目之前，您应该查看一些 python 教程，因为您的家庭作业并不那么容易。

编辑:

根据您发布的新代码，您可以执行如下操作:

def new_game():
  names = []
  for unit_id in range(1,4):
    print(f'Enter a unique name for unit #{unit_id}  ->')
    empty = True                                            
    while empty:
      name = input('>')                                                              
      if name == "":
        continue
      empty = False
      if name in names:
        print('Unit name must be unique.')                                                                              
      else:
        print('Name looks good!')
        names.append(name)

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