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python - 如何为特定用户打开一个窗口 discord.py

转载 作者:行者123 更新时间:2023-12-05 06:57:08 24 4
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我正在编写一个 discord 机器人,您可以通过键入诸如 !pong 之类的命令来玩游戏,它会打开一个窗口来玩经典的乒乓球游戏。问题是,每当除我以外的任何用户键入命令(例如 !snake)时,它都会为我打开窗口,而不是为他们打开窗口。我怎样才能让 window 为他们打开?这是我的代码:

    @client.command()
async def snake(ctx):
await ctx.send(f"Open snake game for {ctx.author.name}...")
# Score
score = 0
high_score = 0

# Set up the screen
wn = turtle.Screen()
wn.title("Snake Game")
wn.bgcolor("green")
wn.setup(width=600, height=600)
wn.tracer(0) # Turns off the screen updates

# Snake head
head = turtle.Turtle()
head.speed(0)
head.shape("square")
head.color("black")
head.penup()
head.goto(0,0)
head.direction = "stop"

# Snake food
food = turtle.Turtle()
food.speed(0)
food.shape("circle")
food.color("red")
food.penup()
food.goto(0,100)

segments = []

# Pen
pen = turtle.Turtle()
pen.speed(0)
pen.shape("square")
pen.color("white")
pen.penup()
pen.hideturtle()
pen.goto(0, 260)
pen.write("Score: 0 High Score: 0", align="center", font=("Courier", 24, "normal"))

# Functions
def go_up():
if head.direction != "down":
head.direction = "up"

def go_down():
if head.direction != "up":
head.direction = "down"

def go_left():
if head.direction != "right":
head.direction = "left"

def go_right():
if head.direction != "left":
head.direction = "right"

def move():
if head.direction == "up":
y = head.ycor()
head.sety(y + 20)

if head.direction == "down":
y = head.ycor()
head.sety(y - 20)

if head.direction == "left":
x = head.xcor()
head.setx(x - 20)

if head.direction == "right":
x = head.xcor()
head.setx(x + 20)

# Keyboard bindings
wn.listen()
wn.onkeypress(go_up, "w")
wn.onkeypress(go_down, "s")
wn.onkeypress(go_left, "a")
wn.onkeypress(go_right, "d")

# Main game loop
while True:
wn.update()

# Check for a collision with the border
if head.xcor()>290 or head.xcor()<-290 or head.ycor()>290 or head.ycor()<-290:
time.sleep(1)
head.goto(0,0)
head.direction = "stop"

# Hide the segments
for segment in segments:
segment.goto(1000, 1000)

# Clear the segments list
segments.clear()

# Reset the score
score = 0

# Reset the delay
delay = 0.1

pen.clear()
pen.write("Score: {} High Score: {}".format(score, high_score), align="center", font=("Courier", 24, "normal"))


# Check for a collision with the food
if head.distance(food) < 20:
# Move the food to a random spot
x = random.randint(-290, 290)
y = random.randint(-290, 290)
food.goto(x,y)

# Add a segment
new_segment = turtle.Turtle()
new_segment.speed(0)
new_segment.shape("square")
new_segment.color("grey")
new_segment.penup()
segments.append(new_segment)

# Shorten the delay
delay -= 0.001

# Increase the score
score += 10

if score > high_score:
high_score = score

pen.clear()
pen.write("Score: {} High Score: {}".format(score, high_score), align="center", font=("Courier", 24, "normal"))

# Move the end segments first in reverse order
for index in range(len(segments)-1, 0, -1):
x = segments[index-1].xcor()
y = segments[index-1].ycor()
segments[index].goto(x, y)

# Move segment 0 to where the head is
if len(segments) > 0:
x = head.xcor()
y = head.ycor()
segments[0].goto(x,y)

move()

# Check for head collision with the body segments
for segment in segments:
if segment.distance(head) < 20:
time.sleep(1)
head.goto(0,0)
head.direction = "stop"

# Hide the segments
for segment in segments:
segment.goto(1000, 1000)

# Clear the segments list
segments.clear()

# Reset the score
score = 0

# Reset the delay
delay = 0.1

# Update the score display
pen.clear()
pen.write("Score: {} High Score: {}".format(score, high_score), align="center", font=("Courier", 24, "normal"))

time.sleep(delay)

wn.mainloop()`

谁能帮帮我?

最佳答案

您不能为他们打开它。你只能为托管机器人的人打开它,如果你想让它工作,你需要他们自己下载机器人并运行它。您可以学习制作基于浏览器的游戏(需要 HTML/CSS/js 知识)并生成新链接,以便他们可以在自己的浏览器上玩游戏。

关于python - 如何为特定用户打开一个窗口 discord.py,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/64962638/

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