Java Spring - 仅保存(POST)来自 ManyToOne 关系的 id

Question

我目前有两个实体:Call 和 CallSource。我在 Call 和 CallSource 之间存在 ManyToOne 关系。我想要的是当我进行 JSON POST 时仅使用 CallSource 的 ID 而不是整个对象并自动为调用生成 CallSource 对象。

调用.java

@Entity
public class Call
{
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;

    private String name;
    private String email;
    private String phone;
    private Date date;

    @ManyToOne
    @JoinColumn(name = "source_id")
    private CallSource source;

    // Constructors, getters and setters
}

调用源

@Entity
public class CallSource
{
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;

    @Column(length = 100)
    private String name;

    // Constructors, getters and setters
}

CallController.java

@RestController
@RequestMapping("api/")
public class CallController
{
    @Autowired
    private CallService callService;

    @RequestMapping(value = "call", method = RequestMethod.POST)
    public Call create(@RequestBody Call call)
    {
        return callService.create(call);
    }

}

CallService.java

@Service
public class CallService
{
    @Autowired
    private CallRepository callRepository;

    public Call create(Call call)
    {
        return callRepository.saveAndFlush(call);
    }
}

CallRepository.java

@Repository
public interface CallRepository extends JpaRepository<Call, Long>
{
}

我想像这样制作一个 JSON POST:

{
      "name": "John Doe",
      "email": "johdoe@example.com",
      "phone": "0000000000",
      "budget": 99999,
      "source": 1
}

实现这一目标的最佳方式是什么？不把source做成对象，json上只有一个字段。

Answer 1

这样就可以了

{
      "name": "John Doe",
      "email": "johdoe@example.com",
      "phone": "0000000000",
      "budget": 99999,
      "source": {"id":1}
}