python - 当通过 raise_for_status 和 python-requests 引发 HTTPError 时如何包含响应

Question

我有一个 API，可以在发生 4xx 错误时返回 json 消息。一个例子是 {'message': 'Could not decode JWT token'} .当我处理异常时，该消息丢失了。

class HttpService:
    def __init__(self, url, token):
        self.headers={"Authorization": token}
        self.requests = Requests(url)

    def get(self, path):
        try:
            response = self.requests.get(path, headers=self.headers)
            response.raise_for_status()

            return response.json()
        except requests.exceptions.RequestException as e:
            raise HttpServiceException(e)

class HttpServiceException(Exception):
    pass

在另一个类中我有一个类似的方法

def get_user(self, user_id):
        try:
            return self.http_service.get("user/" + user_id)
        except HttpServiceException as e:
            print(e) // this prints "401 Client Error: Unauthorized for url: <url>"

我希望能够看到 {'message': 'Could not decode JWT token'}以及 401 Client Error: Unauthorized for url: <url>打印异常时的消息。实现该目标的最佳/最简单方法是什么？

谢谢。

Answer 1

RequestException 具有 request 和 response 属性:

import requests

try:
    response = requests.get('https://httpbin.org/status/403')
    response.raise_for_status()
except requests.exceptions.RequestException as e:
    print(e.request)
    print(e.response)