django - 如何让 Django Graphene ModelForm Mutation 应用

Question

我试图让这个突变在数据库中创建一个新记录。它返回代码 200，但没有对数据库进行任何更改，而且它返回 null。文档在这个问题上并不清楚。(ModelForm vs mutate function)

Graphql 响应:

{
  "data": {
    "addSubjectMark": {
      "subjectMark": null,
      "errors": []
    }
  }
}

根据 django-graphene 文档，我使用 DjangoModelForm 来处理数据库的输入。

我的架构.py:

class SubjectMarkType(DjangoObjectType):
    id = graphene.ID(required=True)
    class Meta:
        model = SubjectMark

class AddSubjectMarkMutation(DjangoModelFormMutation):
    subject_mark = graphene.Field(SubjectMarkType)
    class Meta:
        form_class = ReportForm

class Mutation(graphene.ObjectType):
    add_subject_mark = AddSubjectMarkMutation.Field()

1. 我需要在表单中添加保存方法吗？
2. 我需要使用 mutate 函数吗？(文档不清楚)

谢谢!

Answer 1

ReportForm 应该默认使用 Django，无需修改。缺少的部分是解析 AddSubjectMarkMutation 类中的 subject_mark 属性。

class SubjectMarkType(DjangoObjectType):
    id = graphene.ID(required=True)

    class Meta:
        model = SubjectMark


class AddSubjectMarkMutation(DjangoModelFormMutation):
    subject_mark = graphene.Field(SubjectMarkType)

    class Meta:
        form_class = ReportForm  # NB. make sure ReportForm is able to save in Django

    # you need to resolve subject_mark to return the new object
    def resolve_subject_mark(self, info, **kwargs):
        return self.subjectMark


class Mutation(graphene.ObjectType):
    add_subject_mark = AddSubjectMarkMutation.Field()