gpt4 book ai didi

python - 如何使用 moto 模拟 DynamoDB 分页?

转载 作者:行者123 更新时间:2023-12-05 06:16:31 26 4
gpt4 key购买 nike

我正在测试一些 dynamodb 访问代码。在过去,对分页的不正确处理导致了错误(开发人员倾向于使用少量数据进行手动测试,因此很容易对分页的工作原理做出错误的假设,只有在处理实际数据量时才会出现这种假设)

我通常使用普通 unittestunittest.mock 对访问代码进行单元测试,并以这种方式测试分页,但我最终写了一些合理的复杂的测试代码来模拟不同操作的分页(扫描、查询、batch_get_item)。

我正在寻找一种更简单的测试方法; moto 带来了一些希望

但是,我真的不想将 1MB+ 的数据加载到 moto 中以引起分页,我想强制它对少量数据进行分页

所以我要问的关键是:

  • moto 是否完全支持 DynamoDB 分页?
  • 我可以配置分页阈值吗?
  • 如何?

最佳答案

引用资料

moto 是否完全支持 DynamoDB 分页?

是的,它通过 moto.mock_dynamodb2 功能实现。我尝试使用 PynamoDB 的 query 功能进行分页,它在 moto.mock_dynamodb2 提供的模拟 DynamoDB 环境中运行良好。

我可以配置分页阈值吗?

使用PynamoDB的query,可以在limit参数中配置。

分页具有以下核心概念:

  1. hash_key + range_key_condition + filter_condition
  • 要分页的 DynamoDB 记录列表
  1. 限制
  • 查询返回的最大结果数
  1. scan_index_forward
  • 结果的顺序。您希望按 range_key/sort_key 升序(例如 1、2、3)或降序(例如 3、2、1)对获取的记录进行排序
  1. last_evaluated_key
  • 这表示数据库中最后处理的项目(对于键)。这将该项目标记为将获取下一组项目的引用点。 None 表示从已排序记录的开头查询。否则,从指定的键开始查询。
  • 将其想象成对 [0, 5, 10, 15, 20, 25, 30, 35, 40, 45, 50] 的二进制搜索。如果我们从头开始分页 4 个项目,我们将得到 [0, 5, 10, 15]。如果我们想要获得接下来的 4 个项目,我们不需要从开始(0)一直迭代到目标(20 起)。这种算法在最坏情况下会导致线性 O(n) 时间复杂度,其中 n 是所有记录的计数。相反,我们可以做的是对大于最后获取的项目(15)的第一个项目执行二进制搜索,我们将在对数中得到 20 O(log(n)).

怎么做?

查看 Python 代码片段

# Testing date: 2020 9September 29

# Versions
# moto==1.3.16
# pynamodb==4.3.3
# pytest==6.1.0

import itertools

from moto import mock_dynamodb2
from pynamodb.attributes import *
from pynamodb.models import Model
import pytest


# Model

class Location(Model):
class Meta:
table_name = 'Location-table'
region = 'ap-southeast-1'

continent = UnicodeAttribute(hash_key=True) # also known as partition_key
country = UnicodeAttribute(range_key=True) # also known as sort_key
capital = UnicodeAttribute()
gmt = NumberAttribute()

def __iter__(self):
for name, attr in self.get_attributes().items():
yield name, attr.serialize(getattr(self, name))


# Test data

LOCATIONS = [
{
'continent': 'Europe',
'country': 'Spain',
'capital': 'Madrid',
'gmt': 2,
},
{
'continent': 'Europe',
'country': 'Germany',
'capital': 'Berlin',
'gmt': 2,
},
{
'continent': 'South America',
'country': 'Venezuela',
'capital': 'Caracas',
'gmt': -4,
},
{
'continent': 'Europe',
'country': 'Ukraine',
'capital': 'Kyiv',
'gmt': 3,
},
{
'continent': 'South America',
'country': 'Brazil',
'capital': 'Brasília',
'gmt': -3,
},
{
'continent': 'Europe',
'country': 'Finland',
'capital': 'Helsinki',
'gmt': 3,
},
{
'continent': 'Europe',
'country': 'Ireland',
'capital': 'Dublin',
'gmt': 1,
},
]


# Test algorithms

def _setup_table(locations):
Location.create_table()

for location in locations:
Location(**location).save()

def _get_filter_condition():
# Put logic here for the filter condition. Uncomment the code below to try.
# filter_condition = (Location.gmt >= 2) \
# & (Location.capital.contains('in') | Location.capital.startswith('A'))
# return filter_condition
return None


@mock_dynamodb2
def test_dynamodb_pagination():
_setup_table(LOCATIONS)
filter_condition = _get_filter_condition()

# Expected query order for Europe. This should be sorted by country (which is the sort_key field).
SORTED_EUROPE_COUNTRIES = [
'Finland',
'Germany',
'Ireland',
'Spain',
'Ukraine',
]
country_index = 0

# This indicates the last processed item (for the key) from the database. This marks that item
# as the reference point to where the next set of items will be fetched. None means query from
# the beginning of the sorted records. Otherwise, start the query from the indicated key.
last_evaluated_key = None

for query_index in itertools.count(0):
result = Location.query(
hash_key='Europe',
filter_condition=filter_condition, # Filter the query results
limit=2, # Maximum number of items to fetch from the database
last_evaluated_key=last_evaluated_key, # The reference starting point of the fetch
scan_index_forward=True, # Indicate if in lexicographical order (increasing) or in reverse (decreasing)
)

for item in result:
print(f"Query #{query_index} - Country #{country_index} - {item}")

assert item.country == SORTED_EUROPE_COUNTRIES[country_index]
country_index += 1

print(f"result.last_evaluated_key {result.last_evaluated_key}\n")
last_evaluated_key = result.last_evaluated_key

if last_evaluated_key is None:
print(f"Reached the last queried item in the database")
break

输出:

(venv) nponcian 2020_9Sep_10_DynamoDB$ pytest pagination_test.py -rP
====================================================================================== test session starts ======================================================================================
platform linux -- Python 3.8.2, pytest-6.1.0, py-1.9.0, pluggy-0.13.1
rootdir: /home/nponcian/Documents/Program/2020_9Sep_10_DynamoDB
plugins: cov-2.10.1, mock-3.3.1
collected 1 item

pagination_test.py . [100%]

============================================================================================ PASSES =============================================================================================
___________________________________________________________________________________ test_dynamodb_pagination ____________________________________________________________________________________
------------------------------------------------------------------------------------- Captured stdout call --------------------------------------------------------------------------------------
Query #0 - Country #0 - Location-table<Europe, Finland>
Query #0 - Country #1 - Location-table<Europe, Germany>
result.last_evaluated_key {'continent': {'S': 'Europe'}, 'country': {'S': 'Germany'}}

Query #1 - Country #2 - Location-table<Europe, Ireland>
Query #1 - Country #3 - Location-table<Europe, Spain>
result.last_evaluated_key {'continent': {'S': 'Europe'}, 'country': {'S': 'Spain'}}

Query #2 - Country #4 - Location-table<Europe, Ukraine>
result.last_evaluated_key None

Reached the last queried item in the database
======================================================================================= 1 passed in 0.40s =======================================================================================

关于python - 如何使用 moto 模拟 DynamoDB 分页?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62083300/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com