python - Spotify Python API 调用超时问题

Question

我在调用 Spotify API 时遇到以下错误。是否有解决这些超时问题的方法。 Python Spotify Code

TimeoutError Traceback(最后一次调用)C:\ProgramData\Anaconda3\lib\site-packages\urllib3\util\connection.py in create_connection(address, timeout, source_address, socket_options)73 sock.bind(源地址)---> 74 sock.connect(sa)75回力袜

TimeoutError: [WinError 10060] 连接尝试失败，因为连接方在一段时间后没有正确响应，或者建立的连接失败，因为连接的主机没有响应

在处理上述异常的过程中，又发生了一个异常:

KeyboardInterrupt                         Traceback (most recent call last)
<ipython-input-11-eb4cef5ffdbb> in <module>
      5     #print(artist)
      6     #time.sleep(2)
----> 7     result = spotify.search(artist,search_type='artist')['artists']['items']
      8     #print(result)
      9     try:

<ipython-input-7-6a2d183a2f3a> in search(self, query, search_type)
     80         data = urlencode({"q": query, "type": search_type.lower()})
     81         lookup_url = f"{endpoint}?{data}"
---> 82         r = requests.get(lookup_url, headers=headers)#.json()
     83         if r.status_code not in range(200, 299):
     84             return {}

C:\ProgramData\Anaconda3\lib\site-packages\requests\api.py in get(url, params, **kwargs)
     74 
     75     kwargs.setdefault('allow_redirects', True)
---> 76     return request('get', url, params=params, **kwargs)
     77 
     78 

C:\ProgramData\Anaconda3\lib\site-packages\requests\api.py in request(method, url, **kwargs)
     59     # cases, and look like a memory leak in others.
     60     with sessions.Session() as session:
---> 61         return session.request(method=method, url=url, **kwargs)
     62 
     63 

C:\ProgramData\Anaconda3\lib\site-packages\requests\sessions.py in request(self, method, url, params, data, headers, cookies, files, auth, timeout, allow_redirects, proxies, hooks, stream, verify, cert, json)
    528         }
    529         send_kwargs.update(settings)
--> 530         resp = self.send(prep, **send_kwargs)
    531 
    532         return resp

C:\ProgramData\Anaconda3\lib\site-packages\requests\sessions.py in send(self, request, **kwargs)
    641 
    642         # Send the request
--> 643         r = adapter.send(request, **kwargs)
    644 
    645         # Total elapsed time of the request (approximately)

C:\ProgramData\Anaconda3\lib\site-packages\requests\adapters.py in send(self, request, stream, timeout, verify, cert, proxies)
    437         try:
    438             if not chunked:
--> 439                 resp = conn.urlopen(
    440                     method=request.method,
    441                     url=url,

C:\ProgramData\Anaconda3\lib\site-packages\urllib3\connectionpool.py in urlopen(self, method, url, body, headers, retries, redirect, assert_same_host, timeout, pool_timeout, release_conn, chunked, body_pos, **response_kw)
    668 
    669             # Make the request on the httplib connection object.
--> 670             httplib_response = self._make_request(
    671                 conn,
    672                 method,

C:\ProgramData\Anaconda3\lib\site-packages\urllib3\connectionpool.py in _make_request(self, conn, method, url, timeout, chunked, **httplib_request_kw)
    379         # Trigger any extra validation we need to do.
    380         try:
--> 381             self._validate_conn(conn)
    382         except (SocketTimeout, BaseSSLError) as e:
    383             # Py2 raises this as a BaseSSLError, Py3 raises it as socket timeout.

C:\ProgramData\Anaconda3\lib\site-packages\urllib3\connectionpool.py in _validate_conn(self, conn)
    974         # Force connect early to allow us to validate the connection.
    975         if not getattr(conn, "sock", None):  # AppEngine might not have  `.sock`
--> 976             conn.connect()
    977 
    978         if not conn.is_verified:

C:\ProgramData\Anaconda3\lib\site-packages\urllib3\connection.py in connect(self)
    306     def connect(self):
    307         # Add certificate verification
--> 308         conn = self._new_conn()
    309         hostname = self.host
    310 

C:\ProgramData\Anaconda3\lib\site-packages\urllib3\connection.py in _new_conn(self)
    157 
    158         try:
--> 159             conn = connection.create_connection(
    160                 (self._dns_host, self.port), self.timeout, **extra_kw
    161             )

C:\ProgramData\Anaconda3\lib\site-packages\urllib3\util\connection.py in create_connection(address, timeout, source_address, socket_options)
     72             if source_address:
     73                 sock.bind(source_address)
---> 74             sock.connect(sa)
     75             return sock
     76 

KeyboardInterrupt: 

1
###########Create Data frame with required columns to be extracte


  [1]: /image/lCaz4.p

吴

Answer 1

我真的希望 spotipy 能在他们的包中解决这个问题，但尽管如此，这是我的解决方法:

1. 导入错误类型

如果您没有捕捉到这种确切的错误类型，您就会因为让您的捕捉保持开放状态而给自己带来麻烦。例如，如果您的语法中有 TypeError 之类的东西，它会出错并转到您的 catch block ，而您将无法知道它一开始就出错了。

from requests.exceptions import ReadTimeout

1. 当您初始化 spotipy 客户端时，我建议添加一些可能有用的参数。

spotify = spotipy.Spotify(auth=spotify_token, requests_timeout=10, retries=10)

• 请求超时 |几秒钟后抛出您正在寻找的相同错误。我使用它只是为了它不会永远挂起，如果 10 秒后没有返回，它只会重试请求。
• 重试 |如果出现错误，spotipy 将请求的最大重试次数。我认为它默认为 3，所以我只是想增加一点以防万一。

1. 运行 try/except 类型的重试系统

如果它一直挂起，您绝对可以扩展它以使其不断重试(使用 while 循环或其他东西)，但这是基本思想:

try:

  result = spotify.search(artist,search_type='artist')['artists']['items']

except ReadTimeout:

  print('Spotify timed out... trying again...')
  result = spotify.search(artist,search_type='artist')['artists']['items']