python - 如何让 Selenium 等到找到元素而不是使用 time.sleep()

Question

基本上，我正在构建一个小脚本来自动化一些基本的东西。我一直在使用 time.sleep() 让软件稍等片刻，直到所有内容都加载完毕，但是否有更好的方法来做到这一点？？

我希望脚本自行等待必要的时间，以使事情变得更快、更干净。

from selenium import webdriver

from selenium.webdriver.common.keys import Keys
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import Select
import time
from tkinter import *


def cs_update():

    PATH = "C:\Program Files (x86)\chromedriver.exe"
    options = Options()
    options.headless = True



    driver = webdriver.Chrome(PATH,options = options) 
    driver.set_window_size(1920,1080)
    driver.minimize_window()

    user_email = e.get()
    user_password = e2.get()

    driver.get("https://www.compraensanjuan.com")
    time.sleep(3)


    link = driver.find_element_by_link_text("Mi cuenta")

    link.click()
    time.sleep(3)

    email = driver.find_element_by_name("email")

    email.send_keys(user_email)

    print("I sent the keys")

Answer 1

这就是您可以使用 ExplicitWait 的方式

from selenium.webdriver.common.by import By 
from selenium.webdriver.support.ui import WebDriverWait 
from selenium.webdriver.support import expected_conditions as EC

driver.get("https://www.compraensanjuan.com")

timeout = 20 # set seconds to wait until TimeOutException raised
link = WebDriverWait(driver, timeout).until(EC.element_to_be_clickable((By.LINK_TEXT, "Mi cuenta")))

link.click()

email = WebDriverWait(driver, timeout).until(EC.presence_of_element_located((By.NAME, "email")))