gpt4 book ai didi

javascript - 如何从此 AWS SecretsManager JSON 对象中提取字段?

转载 作者:行者123 更新时间:2023-12-05 05:58:26 25 4
gpt4 key购买 nike

我正在使用 AWS Secrets Manager 来保护我的 REST API 的数据库积分。我正在使用 AWS Lambda、API 网关和 RDS (MySQL)。以下是我如何获得它们。

// Load the AWS SDK
var AWS = require('aws-sdk'),
region = "us-east-1",
secretName = "test-secret",
secret,
decodedBinarySecret;

// Create a Secrets Manager client
var client = new AWS.SecretsManager({
region: region
});

// In this sample we only handle the specific exceptions for the 'GetSecretValue' API.
// See https://docs.aws.amazon.com/secretsmanager/latest/apireference/API_GetSecretValue.html
// We rethrow the exception by default.
exports.handler = (event, context, callback) => {
client.getSecretValue({
SecretId: secretName
}, function(err, data) {
if (err) {
throw err
} else {
// Decrypts secret using the associated KMS CMK.
// Depending on whether the secret is a string or binary, one of these fields will be populated.
if ('SecretString' in data) {
secret = data.SecretString;
} else {
let buff = new Buffer(data.SecretBinary, 'base64');
decodedBinarySecret = buff.toString('ascii');
}
}
// Your code goes here.
console.log(secret);
});
};

下面是输出

INFO    {"username":"***","password":"***","engine":"mysql","host":"***.***.us-east-1.rds.amazonaws.com","port":3306,"dbname":"***","dbInstanceIdentifier":"***"}

我试过像下面这样提取密码

let pass = secret.password;
console.log(pass);

它给出了以下内容

INFO    undefined

如何提取passwordusernamedatabasename等字段?

最佳答案

一开始,你得到的secretdata.SecretString,现在secret只是一个普通的字符串。在您的情况下,它是一个 JSON 字符串,您必须将您的字符串转换为 JSON 对象,然后您可以轻松地通过属性名称访问信息。

为此,您可以使用 JSON.parse将 json 字符串转换为 json 对象的方法:

var secret = `{"username":"***","password":"***","engine":"mysql","host":"***.***.us-east-1.rds.amazonaws.com","port":3306,"dbname":"***","dbInstanceIdentifier":"***"}
`;

const secretObj = JSON.parse(secret);

console.log(secretObj.host)

关于javascript - 如何从此 AWS SecretsManager JSON 对象中提取字段?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/68480980/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com