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python - groupby 后找不到 Grouper 名称 `datetime`

转载 作者:行者123 更新时间:2023-12-05 05:51:39 24 4
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我有这个 Pandas 数据框

        datetime       machineID    errorID
0 2015-01-06 03:00:00 1 error3
1 2015-02-03 06:00:00 1 error4
2 2015-02-21 11:00:00 1 error1
3 2015-02-21 16:00:00 1 error2
4 2015-03-20 06:00:00 1 error1
5 2015-04-04 06:00:00 1 error5
6 2015-05-04 06:00:00 1 error4
7 2015-05-19 06:00:00 1 error2
8 2015-05-19 06:00:00 1 error3
9 2015-06-03 06:00:00 1 error5

现在我想拆开 errorID,这样我就可以获取基于 error1error2...error5 的列。为此,我在 Pandas 中使用了 groupby 和 unstack 方法

a = errors.groupby(['machineID', 'datetime', 'errorID']).size().unstack('errorID', fill_value=0)

这给了我这个数据框

             errorID    error1  error2  error3  error4  error5
machineID datetime
1 2015-01-06 03:00:00 0 0 1 0 0
2015-02-03 06:00:00 0 0 0 1 0
2015-02-21 11:00:00 1 0 0 0 0
2015-02-21 16:00:00 0 1 0 0 0
2015-03-20 06:00:00 1 0 0 0 0

现在我想根据 24H 频率和 datetime 对这些数据重新采样。但是当我使用 resample 函数时,它给我错误 KeyError: 'The grouper name datetime is not found'

a.resample('24H', on='datetime').agg({'error1':'mean','error2':'mean','error3':'mean','error4':'mean', 'error5':'mean'}).rename(columns={'error1':'error1_mean','error2' : 'error2_mean', 'error3': 'error3_mean', 'error4': 'error4_24mean','error5': 'error5_24mean'})

当我列出此数据框中的所有列时,它仅显示 ['error1', 'error2', 'error3', 'error4', 'error5']

这是整个错误

---------------------------------------------------------------------------
KeyError Traceback (most recent call last)
<ipython-input-127-607c418305a0> in <module>
----> 1 a.resample('24H', on='datetime').agg({'error1':'mean','error2':'mean','error3':'mean','error4':'mean', 'error5':'mean'}).rename(columns={'error1':'error1_mean','error2' : 'error2_mean', 'error3': 'error3_mean', 'error4': 'error4_24mean','error5': 'error5_24mean'})

/anaconda/envs/azureml_py36/lib/python3.6/site-packages/pandas/core/generic.py in resample(self, rule, how, axis, fill_method, closed, label, convention, kind, loffset, limit, base, on, level)
8447 base=base,
8448 key=on,
-> 8449 level=level,
8450 )
8451 return _maybe_process_deprecations(

/anaconda/envs/azureml_py36/lib/python3.6/site-packages/pandas/core/resample.py in resample(obj, kind, **kwds)
1304 """
1305 tg = TimeGrouper(**kwds)
-> 1306 return tg._get_resampler(obj, kind=kind)
1307
1308

/anaconda/envs/azureml_py36/lib/python3.6/site-packages/pandas/core/resample.py in _get_resampler(self, obj, kind)
1428
1429 """
-> 1430 self._set_grouper(obj)
1431
1432 ax = self.ax

/anaconda/envs/azureml_py36/lib/python3.6/site-packages/pandas/core/groupby/grouper.py in _set_grouper(self, obj, sort)
171 else:
172 if key not in obj._info_axis:
--> 173 raise KeyError("The grouper name {0} is not found".format(key))
174 ax = Index(obj[key], name=key)
175

KeyError: 'The grouper name datetime is not found'

我不知道如何在 groupby 之后使用重采样

最佳答案

首先将值转换为日期时间:

errors['datetime'] = pd.to_datetime(errors['datetime'])

a = errors.groupby(['machineID', 'datetime', 'errorID']).size().unstack('errorID', fill_value=0)

然后如果需要对每个 machineID resample 使用:

a = a.reset_index(level=0).groupby('machineID').resample('24H').agg({'error1':'mean','error2':'mean','error3':'mean','error4':'mean', 'error5':'mean'}).rename(columns={'error1':'error1_mean','error2' : 'error2_mean', 'error3': 'error3_mean', 'error4': 'error4_24mean','error5': 'error5_24mean'})

或者如果只需要resample使用:

a = a.reset_index(level=0).resample('24H').agg({'error1':'mean','error2':'mean','error3':'mean','error4':'mean', 'error5':'mean'}).rename(columns={'error1':'error1_mean','error2' : 'error2_mean', 'error3': 'error3_mean', 'error4': 'error4_24mean','error5': 'error5_24mean'})

或者如果需要 groupby 和 Grouper 使用:

a = a.groupby(['machineID', pd.Grouper(freq='24H', level='datetime')]).agg({'error1':'mean','error2':'mean','error3':'mean','error4':'mean', 'error5':'mean'}).rename(columns={'error1':'error1_mean','error2' : 'error2_mean', 'error3': 'error3_mean', 'error4': 'error4_24mean','error5': 'error5_24mean'})

关于python - groupby 后找不到 Grouper 名称 `datetime`,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/70346473/

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