- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
出于某种原因,当我尝试运行贪吃蛇游戏时,它总是提示没有响应。它以前曾经工作过,但现在似乎已经停止了。它在 replit 中似乎也不起作用。我对 pygame 很陌生,所以我以前从未遇到过这个问题。我试过重新运行它并进行小的编辑,但到目前为止没有任何效果。为什么会这样,我该如何解决?
代码如下:
import random
# initialize pygame
pygame.init()
# defining colour variables using rgb
white = (255, 255, 255)
pink = (255, 158, 208)
black = (0, 0, 0)
red = (213, 50, 80)
yellow = (237, 255, 41)
blue = (50, 153, 213)
# screen width and height
WIN_WIDTH = 600
WIN_HEIGHT = 400
# set the window, valid arguments are width and height
WIN = pygame.display.set_mode((WIN_WIDTH, WIN_HEIGHT))
pygame.display.set_caption('snake game')
clock = pygame.time.Clock()
# size the snake (rectangle)
snake_block = 10
# set the snakes velocity (speed)
VEL = 15
# define fonts, valid arguments are the font name and size
font_style = pygame.font.SysFont('bahnschrift', 25)
score_font = pygame.font.SysFont('impact', 30)
# score function
def score(score):
text = score_font.render(' Score: ' + str(score), True, pink) # create the score
WIN.blit(text, [0, 0]) # using blit to add the text to the screen
# snake function, passing in snake block and snake list (see game loop)
def snake(snake_block, snake_list):
for x in snake_list:
pygame.draw.rect(WIN, black, [x[0], x[1], snake_block, snake_block]) # creating the snake rectangle
def message(msg, colour):
msg = font_style.render(msg, True, colour) # renders a font
WIN.blit(msg, [WIN_WIDTH / 6, WIN_HEIGHT / 3]) # blits the msg coordinates
# main gameloop function
def gameLoop():
# boolean variables
game_over = False
game_close = False
# x and y variables for where the snake will be placed
x1 = WIN_WIDTH / 2
y1 = WIN_HEIGHT / 2
# create x and y change variables to update the coordinates
x1_change = 0
y1_change = 0
# creating an empty list for the snakes length
snake_List = []
Length_of_snake = 1
# add a randomly placed rectangle that will act as the food (x, y)
foodx = round(random.randrange(0, WIN_WIDTH - snake_block) / 10.0) * 10.0
foody = round(random.randrange(0, WIN_HEIGHT - snake_block) / 10.0) * 10.0
# while the game isn't over
while not game_over:
# while game close is true
while game_close:
# turn the screen blue
WIN.fill(blue)
# add losing text
message('You Lost! Press C to Play Again or Q to Quit', red)
# sets the score for when you lost
score(Length_of_snake - 1)
pygame.display.update()
# pygame events
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit() # making it so when the user clicks the x the game closes
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_q: # same thing as the x in the corner, but you can press q
game_over = True
game_close = False
if event.key == pygame.K_c: # replay the game
gameLoop() # calls the main function (restarts)
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_over = True
if event.type == pygame.KEYDOWN: # keydown is another event, for using the keyboard to do stuff
if event.key == pygame.K_a: # if the a key is pressed, x1_change = -snake_block, which is equal to 10. this moves the rectangle to the left
x1_change = -snake_block
y1_change = 0
if event.key == pygame.K_d: # if the d key is pressed, x1_change = snake_block, which is equal to 10. this moves the rectangle to the right
x1_change = snake_block
y1_change = 0
if event.key == pygame.K_w: # if the w key is pressed, y1_change = -snake_block, which is equal to 10. this moves the rectangle up
y1_change = -snake_block
x1_change = 0
if event.key == pygame.K_s: # if the s key is pressed, y1_change = snake_block, which is equal to 10. this moves the rectangle down
y1_change = snake_block
x1_change = 0
if x1 >= WIN_WIDTH or x1 < 0 or y1 >= WIN_HEIGHT or y1 < 0: # if the x or y positions of the snake go over the screen width or height
game_close = True # you lose
x1 += x1_change
y1 += y1_change
WIN.fill(blue)
pygame.draw.rect(WIN, yellow, [foodx, foody, snake_block, snake_block])
snake_Head = [] # create a snake head empty list
snake_Head.append(
x1) # append lets us add something to a list, in this case x1 and y1 are added to the snake_head list
snake_Head.append(y1)
snake_List.append(snake_Head) # add snake head to snake list
if len(snake_List) > Length_of_snake: # len returns the length of something, in this case snake list, so if snake list is greater than the snakes length
del snake_List[0] # del means delete, so delete the first value in snake list, index 0
for i in snake_List[:-1]:
if i == snake_Head: # if the snake head hits itself
game_close = True # you lose
snake(snake_block, snake_List)
score(Length_of_snake - 0)
pygame.display.update() # update the screen
if x1 == foodx and y1 == foody: # if you hit the food
foodx = round(
random.randrange(0, WIN_WIDTH - snake_block) / 10.0) * 10.0 # generate a new random food position
foody = round(random.randrange(0, WIN_HEIGHT - snake_block) / 10.0) * 10.0
Length_of_snake += 1 # add 1 to the snakes length
clock.tick(VEL) # valid arguments are a number (frames per second)
# oposite of pygame.init, quit
pygame.quit()
# quit the program
quit()
# call the gameloop function
gameLoop()
最佳答案
参见 Faster version of 'pygame.event.get()'. Why are events being missed and why are the events delayed? . pygame.event.get()
获取所有消息并将它们从队列中删除。请参阅文档:
This will get all the messages and remove them from the queue. [...]
如果在多个事件循环中调用 pygame.event.get()
,则只有一个循环接收事件,但绝不会所有循环都接收所有事件。结果,一些事件似乎被遗漏了。只实现 1 个事件循环。
不要递归调用 gameLoop
,而是循环运行游戏。递归调用 main 函数会弄乱您的变量,实际上会导致游戏在游戏中运行。
例如:
def gameLoop():
# run the game in a loop multiple times
game_close = False
while not game_close:
# init game states
x1 = WIN_WIDTH / 2
y1 = WIN_HEIGHT / 2
# [...]
# application loop
game_over = False
while not game_over:
# [...]
# pygame events
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_over = True
game_close = True
if event.type == pygame.KEYDOWN: # keydown is another event, for using the keyboard to do stuff
if event.key == pygame.K_q: # same thing as the x in the corner, but you can press q
game_over = True
game_close = True
if event.key == pygame.K_c: # replay the game
game_over = True
if event.key == pygame.K_a: # if the a key is pressed, x1_change = -snake_block, which is equal to 10. this moves the rectangle to the left
x1_change = -snake_block
y1_change = 0
# [...]
关于python - 运行代码时 Pygame 没有响应,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/71298756/
我正在尝试检查 Entry 中是否存在重复项,并使用内联消息提醒用户该数字存在。 $(document).ready(function(){ $("#con1").blur(function(
我有一个基于类的 View 。我在引导模式上使用 Ajax。为了避免页面刷新,我想使用此类基于 View 返回 JSON 响应而不是 HTTP 响应,但我只看到了如何为基于函数的 View 返回 JS
关闭。这个问题是not reproducible or was caused by typos .它目前不接受答案。 这个问题是由于错别字或无法再重现的问题引起的。虽然类似的问题可能是on-topi
我有一个大型内部企业基于 Web 的应用程序在 IIS6 上运行 ASP.NET 3.5,生成 401 个“未经授权”响应,然后是 200 个“Ok”响应(如 Fiddler 所述)。我知道为什么会发
感谢您研究我的问题。 我有一个node/express服务器,配置了一个server.js文件,它调用urls.js,而urls.js又调用 Controller 来处理http请求,所有这些都配置相
当我使用以下命令时,我得到正确的 JSON 响应: $ curl --data "regno=&dob=&mobile=" https://vitacademics-rel.herokuapp.co
我有一个非常简单的 RESTful 服务,它通过 POST 接收一些表单数据,其目的是在云存储(Amazon S3、Azure Blob 存储等)中简单地保留文本主体(具有唯一 ID)作为一个文件..
UDP 不发送任何 ack,但它会发送任何响应吗? 我已经设置了客户端服务器UDP程序。如果我让客户端向不存在的服务器发送数据,那么客户端会收到任何响应吗? 我的假设是; 客户端 --> 广播服务器地
我有一个电梯项目,其中 有一个扩展 RestHelper 的类,看起来像这样 serve{ "api" / "mystuff" prefix { case a
我们正在寻求覆盖 Kong 错误响应结构并编写自定义消息(即用我们的自定义消息替换“超出 API 速率限制”、“无效的身份验证凭据”等)。 我们要找的错误响应结构(代码是自定义的内部错误代码,与HTT
我正在尝试监听 EKEventStoreChangedNotification 以检查当我的应用程序处于后台时日历是否已更改。 我在 View Controller 的 initWithNibMeth
我了解 javascript,并且正在学习 ASP.NET C# 我想要做什么(完成的是javascript): document.getElementById('divID-1'
是否可以过滤所有 har 对象并仅获取 POST 请求/响应?也许在初始化 BrowserMobProxyServer 期间是这样做的方法?我需要将 har 对象保存到文件中并上传到 har 查看器。
我正在尝试向 Oauth 的 API 发送响应。遗憾的是,Symfony2 文档在解释 $response->headers->set(...); 的所有不同部分方面做得很差。 这是我的 OauthC
我正在尝试测试用例来模拟 api 调用,并使用 python 响应来模拟 api 调用。 下面是我的模拟, with responses.RequestsMock() as rsps: url
在尝试在 Haskell 中进行一些领域驱动设计时,我发现自己遇到了这个问题: data FetchAccessories = FetchAccessories data AccessoriesRes
我正在与 ANT+ USB 棒连接,并用项目 react 器替换我自己天真的“MessageBus”,因为它看起来非常合适。 USB接口(interface)本质上是异步的(单独的输入/输出管道),我
我正在将项目迁移到AFNetworking 2.0。使用AFNetworking 1.0时,我编写了代码来记录控制台中的每个请求/响应。这是代码: -(AFHTTPRequestOperation *
我有以下代码段。 ajaxRequest.onreadystatechange = function(){ if(ajaxRequest.readyState == 4){
我有问题......我在 php 中有一个监听器脚本可以执行以下操作: if ($count != 1) {echo 'no';} else { echo "yes";} 因此它会回显"is"或“
我是一名优秀的程序员,十分优秀!