r - 为什么我在 `vec_as_location()` : when computing count and full join function? 中出现错误

Question

我用我想要的变量名创建了对象，并为导入的数据选择了变量。但是当我使用 full_join 或 count 时，它一直在 vec_as_location(): 中给我错误。有谁知道如何避免这个错误？我一个月前写的代码也出现了这个错误。但一个月前它奏效了。

vars <- c("pidp", "cb_age")

wave1 <- read_dta("./data/dresp_w.dta",
                  col_select = vars)
vars2 <- c("pidp", "cb_sex")

wave2 <- read_dta("./data/dresp_w.dta",
                  col_select = vars2)
wave12 <- full_join(wave1, wave2, by = "pidp")
count(wave1,cb_sex)

dput(head(wave1)) 的输出dput(head(wave2)) 将是:

structure(list(pidp = structure(c(76165, 280165, 599765, 732365, 
1587125, 3424485), label = "Cross-wave Person Identifier (Public Release)", format.stata = "%12.0g"), 
    cb_age = structure(c(37, 40, 33, 34, 54, 84), label = "Age - derived", format.stata = "%8.0g", labels = c(Missing = -9, 
    Inapplicable = -8, Refusal = -2, `Don't know` = -1), class = c("haven_labelled", 
    "vctrs_vctr", "double"))), row.names = c(NA, -6L), class = c("tbl_df", 
"tbl", "data.frame"))

structure(list(pidp = structure(c(76165, 280165, 599765, 732365, 
1587125, 3424485), label = "Cross-wave Person Identifier (Public Release)", format.stata = "%12.0g"), 
    cb_sex = structure(c(2, 2, 2, 1, 2, 2), label = "Respondent sex", format.stata = "%8.0g", labels = c(Missing = -9, 
    Inapplicable = -8, Refusal = -2, `Don't know` = -1, Male = 1, 
    Female = 2), class = c("haven_labelled", "vctrs_vctr", "double"
    ))), row.names = c(NA, -6L), class = c("tbl_df", "tbl", "data.frame"
))  

谢谢你的帮助!!

Answer 1

它似乎与 dplyr packageVersion -1.0.9 一起工作得很好

dplyr::count(wave2, cb_sex)
# A tibble: 2 × 2
      cb_sex     n
   <dbl+lbl> <int>
1 1 [Male]       1
2 2 [Female]     5