python - 基于 slug 的 Django 查询集过滤器

Question

我想在显示视频的页面上放置一个过滤器，选择一个专辑显示在专辑页面上，而不是所有视频，但我当前的过滤器显示所有已发布的视频。我找不到一种方法来放置基于 slug 的过滤器，如果专辑的 slug 与当前 url 匹配，则显示选择该专辑的视频。例如:- Gaurav 创建的视频只能在 Gaurav 的相册中看到，其他任何人都不能看到。我很困惑帮助我。

模型.py

from django.db import models
from django.urls import reverse

STATUS = (
    (1, "Publish"),
    (0, "Draft")
)

class WatchCategory(models.Model):
    title = models.CharField(max_length=20)
    slug = models.SlugField(max_length=2000, unique=True)

    def __str__(self):
        return self.title


class Genre(models.Model):
    title = models.CharField(max_length=20)
    slug = models.SlugField(max_length=2000, unique=True)

    def __str__(self):
        return self.title
    class Album(models.Model):
        title = models.CharField(max_length=2000)
        slug = models.SlugField(max_length=2000, unique=True)
        image = models.CharField(max_length=2000, blank=True)
    
        def __str__(self):
            return self.title
    
        def get_absolute_url(self):
            return reverse('Watch:album', kwargs={
                'slug': self.slug
            })
    
    
    class Video(models.Model):
        title = models.CharField(max_length=2000)
        slug = models.SlugField(max_length=2000, unique=True)
        thumbnail = models.CharField(max_length=2000, unique=True)
        updated_on = models.DateTimeField(auto_now=True)
        file = models.CharField(max_length=2000)
        time = models.CharField(max_length=2000, blank=True)
        about = models.TextField(blank=True)
        category = models.ManyToManyField(WatchCategory)
        album = models.ManyToManyField(Album)
        genre = models.ManyToManyField(Genre)
        created_on = models.DateTimeField(auto_now_add=True)
        status = models.IntegerField(choices=STATUS, default=1)
    
        class Meta:
            ordering = ['-created_on']
    
        def __str__(self):
            return self.title
    
        def get_absolute_url(self):
            return reverse('Watch:video', kwargs={
                'slug': self.slug
            })
    

View .py

        class Album(ListView):
            queryset = Video.objects.filter(status=1).order_by('-created_on')
            template_name = 'Watch/album.html'
            paginate_by = 6

            def get_context_data(self, **kwargs):
                context = super().get_context_data(**kwargs)
                context['title'] = 'Explore & Watch your favourite'
                return context

相册.html

        {% extends "Watch/layout.html" %}
        {% load static %}
        {% block content %}

            <div class="video-block section-padding">
                <div class="row">
                    {% for video in video_list %}
                    <div class="col-xl-3 col-sm-6 mb-3">
                        <div class="video-card">
                            <div class="video-card-image">
                                <a class="play-icon" href="{% url 'Watch:video' video.slug %}"><i class="fas fa-duotone fa-circle-play"></i></a>
                                <a href="{% url 'Watch:video' video.slug %}"><img class="img-fluid" src="{{ video.thumbnail }}" alt=""></a>
                                <div class="time">{{ video.time }}</div>
                            </div>
                            <div class="video-card-body">
                                <div class="video-title">
                                    <a href="{% url 'Watch:video' video.slug %}">{{ video.title }}</a>
                                </div>
                            </div>
                        </div>
                    </div>
                    {% endfor %}
                </div>
            </div>

        {% endblock %}

Answer 1

我在 get_context_data() 中也遇到过同样的问题

def get_context_data(self, **kwargs):
    context = super().get_context_data(**kwargs)
    movies = Video.objects.filter(slug=SlugField) #SlugField is the source of the problem I got I think
    context["movies"] = movies
    return context

但是它不起作用，你还尝试了什么？