javascript - 随机ID功能。通过 prompt() 得到 ID 的长度和 Id 的数量

Question

我尝试构建一个函数，该函数应该输出 x 数量的 id 和 y 长度。 IDs的数量和Ids的长度由用户通过提示输入。

这是我到目前为止尝试过的:

function userIdGenerator() {
    let amountOfId = prompt('Please enter the amount of IDs')
    let lengthOfId = prompt('Please enter the lenght of your ID(s)')
    let userId = ''
    let userIds = []
    let stringValues ='ABCDEFGHIJKLMNOabcdefghijklmnopqrstuvwxyzPQRSTUVWXYZ0123456789'
    let numOfChar = stringValues.length
    
    for(let i = 0; i < amountOfId; i++){
        for(let i = 0; i < lengthOfId; i++){
            if( i< lengthOfId  ){
                userId += stringValues.charAt(Math.round(Math.random() * numOfChar))
            }else{
                userIds.push(userId)
            }
        }
    }
    console.log(userIds)
}

我得到一个空数组作为输出。当我删除 else 语句和 console.log(userId) 时，我得到一个长度为 x*y 的字符串，所以我想知道如何改进这个函数。

谢谢你的帮助，

威利

Answer 1

我在评论中更改了一些内容。

function userIdGenerator() {
  let amountOfId = prompt('Please enter the amount of IDs')
  let lengthOfId = prompt('Please enter the lenght of your ID(s)')
  let userId = "";
  let userIds = [];
  let stringValues =
    "ABCDEFGHIJKLMNOabcdefghijklmnopqrstuvwxyzPQRSTUVWXYZ0123456789";
  let numOfChar = stringValues.length;

  for (let i = 0; i < amountOfId; i++) {
// you need to reset the userId each time you're starting to build a new one, otherwise that's why you'd get a string that has the lenght of x*y
    userId = "";
    for (let i = 0; i < lengthOfId; i++) {
// there is no need for a if statement on i < lengthOfId, since by definition of your for loop, it's gonna stop before it's the case.
      userId += stringValues.charAt(Math.round(Math.random() * numOfChar));
    }
// you need to push only once you're done adding all the characters
    userIds.push(userId);
  }
  console.log(userIds);
}