json - 是否可以编写通用的 JSON Schema？

Question

在我的根 JSON 对象中，我有许多两种不同类型的 JSON 对象。我想知道是否有一种方法可以编写 JSON 模式来验证这些对象而无需获取特定的(即通用模式)。

例如，假设我有以下 JSON:

"Profile":
{
    "Name":
    {
        "Type": "String",
        "Value": "Mike",
        "Default": "Sarah",
        "Description": "This is the name of my person."
    }
    "Age":
    {
        "Type": "Number",
        "Value": 27,
        "Default": 18,
        "Description": "This is the age of my person."
    }
}

此配置文件 JSON 对象表示关于一个人的各种详细信息的集合。请注意，我有两种不同类型的内部对象，字符串对象和数字对象。考虑到这一点，我现在想创建一个 JSON 模式来验证任何内部对象，而不是具体说明它们是哪些对象，例如我不关心我们有“姓名”或“年龄”，我关心我们有适当的字符串对象和数字对象。

JSON Schema 是否提供了执行此操作的能力？如何根据我拥有的对象种类而不是特定对象名称编写通用 JSON 架构？

这是我到目前为止所得到的:

{
"$schema": "http://json-schema.org/draft-04/schema#",
  "definitions": {
    "StringObject": {
      "type": "object",
      "properties": {
        "Type": {
          "type": "string"
        },
        "Value": {
          "type": "string"
        },
        "Default": {
          "type": "string"
        },
        "Description": {
          "type": "string"
        }
      },
      "required": [
        "Type",
        "Value",
        "Default",
        "Description"
      ]
    }
  }
}

Answer 1

Inside my root JSON object I have many JSON objects of two different types. I'm wondering if there is a way to write a JSON schema to validate these objects without getting specific, i.e. generic schema.

定义联合类型来处理这个:

A value of the "union" type is encoded as the value of any of the member types.

Union type definition - An array with two or more items which indicates a union of type definitions. Each item in the array may be a simple type definition or a schema.

{
"type":
  ["string","number"]
}

引用资料

• JSON Encoding of Data Modeled with YANG: 6.10. The "union" Type

• A JSON Media Type for Describing the Structure and Meaning of JSON Documents: Union Types