sql-server - 根据值将SQL列拆分为多个列

Question

我有一个像下面这样的表格

Opp_ID     Role_Name     Role_User_Name
---------------------------------------
1          Lead          Person_one
1          Developer     Person_two
1          Developer     Person_three
1          Owner         Person_four
1          Developer     Person_five

我现在需要根据值将 Role_Name 列拆分为 3 个不同的列。我需要确保没有 NULL 值，所以表格应该如下所示

Opp_ID     Lead        Developer     Owner
--------------------------------------------------
1          Person_one  Person_two    Person_four
1          Person_one  Person_three  Person_four
1          Person_one  Person_five   Person_four

我的代码目前是:

SELECT
    ID,
    CASE WHEN Role_Name = 'Lead' THEN Role_User_Name ELSE NULL END AS Lead,
    CASE WHEN Role_Name = 'Developer' THEN Role_User_Name ELSE NULL END AS Developer,
    CASE WHEN Role_Name = 'Owner' THEN Role_User_Name ELSE NULL END AS Owner
FROM 
    [table1]
WHERE 
    Role_Name IN ('Lead','Developer','Owner')

不幸的是，这会返回这些结果:

Opp_ID     Lead        Developer     Owner
-------------------------------------------
1          Person_one  NULL          NULL
1          NULL        Person_two    NULL
1          NULL        Person_three  NULL
1          NULL        NULL          Person_four
1          NULL        Person_five   NULL

我假设要让它正常工作，您需要将代码重新加入自身，但我似乎无法让它正常工作。

Answer 1

要为每个开发人员申请一个 Opp_ID 并引导您的所有者，您需要如下内容:

SELECT o.opp_id
    , o.Role_User_Name AS Owner
    , l.Role_User_Name AS Lead
    , d.Role_User_Name AS Developer
FROM t1 AS o
LEFT OUTER JOIN t1 l ON o.opp_id = l.opp_id AND l.Role_Name = 'Lead'
LEFT OUTER JOIN t1 d ON o.opp_id = d.opp_id AND d.Role_Name = 'Developer'
WHERE o.Role_Name = 'Owner'

https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=da4daea062534245bed474f93ffafbb7