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Ruby:如何仅从 unicode 文本中分解打印连字?

转载 作者:行者123 更新时间:2023-12-05 04:36:41 25 4
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我正在寻找一种方法来规范化 unicode 输入文本,其中包括打印连字,例如

# Things to replace, for instance:
U+FB00 (ff): ff
U+FB01 (fi): fi
U+FB02 (fl): fl
U+FB03 (ffi): ffi
U+FB04 (ffl): ffl
U+FB05 (ſt): st
U+FB06 (st): st

我想保留所有变音符号、标点符号和其他可以分解但不是打印连字的标记。

例如,我想保留商标符号或省略号。

# Things to keep, for instance:
U+2122 (™): TM
U+2026 (…): ...
U+2120 (℠): SM
U+2121 (℡): TEL

我搜索了一个解决方案,找到了一些相关的答案:

是否有特定于 Ruby 的方法?

最佳答案

我目前的 hackish 解决方案:

  def self.remove_ligatures input

@@ligature_char_regex ||= /[#{ligature_chars.join('')}]/

input.gsub(@@ligature_char_regex) { |c|
c.unicode_normalize(:nfkc)
}

end

这可行,但依赖于手动定义的一长串字符(见下文),并且在性能方面可能不是最快的方法。

  # Return the list of all characters which decompose 
# into multiple ascii/accented characters
#
# Manually commented out those that are not typographic
# ligatures such as Trademark, Medical Doctor, CD
#
# List from: https://superuser.com/questions/669130/double-latin-letters-in-unicode-ligatures
def self.ligature_chars

return [
"\u0132", # (IJ): IJ
"\u0133", # (ij): ij
"\u01C7", # (LJ): LJ
"\u01C8", # (Lj): Lj
"\u01C9", # (lj): lj
"\u01CA", # (NJ): NJ
"\u01CB", # (Nj): Nj
"\u01CC", # (nj): nj
"\u01F1", # (DZ): DZ
"\u01F2", # (Dz): Dz
"\u01F3", # (dz): dz
"\u20A8", # (₨): Rs
"\u2116", # (№): No
# "\u2120", # (℠): SM
# "\u2121", # (℡): TEL
# "\u2122", # (™): TM
"\u213B", # (℻): FAX
"\u2161", # (Ⅱ): II
"\u2162", # (Ⅲ): III
"\u2163", # (Ⅳ): IV
"\u2165", # (Ⅵ): VI
"\u2166", # (Ⅶ): VII
"\u2167", # (Ⅷ): VIII
"\u2168", # (Ⅸ): IX
"\u216A", # (Ⅺ): XI
"\u216B", # (Ⅻ): XII
"\u2171", # (ⅱ): ii
"\u2172", # (ⅲ): iii
"\u2173", # (ⅳ): iv
"\u2175", # (ⅵ): vi
"\u2176", # (ⅶ): vii
"\u2177", # (ⅷ): viii
"\u2178", # (ⅸ): ix
"\u217A", # (ⅺ): xi
"\u217B", # (ⅻ): xii
"\u3250", # (㉐): PTE
"\u32CC", # (㋌): Hg
"\u32CD", # (㋍): erg
"\u32CE", # (㋎): eV
"\u32CF", # (㋏): LTD
"\u3371", # (㍱): hPa
"\u3372", # (㍲): da
"\u3373", # (㍳): AU
"\u3374", # (㍴): bar
"\u3375", # (㍵): oV
"\u3376", # (㍶): pc
"\u3377", # (㍷): dm
"\u337A", # (㍺): IU
"\u3380", # (㎀): pA
"\u3381", # (㎁): nA
"\u3383", # (㎃): mA
"\u3384", # (㎄): kA
"\u3385", # (㎅): KB
"\u3386", # (㎆): MB
"\u3387", # (㎇): GB
"\u3388", # (㎈): cal
"\u3389", # (㎉): kcal
"\u338A", # (㎊): pF
"\u338B", # (㎋): nF
"\u338E", # (㎎): mg
"\u338F", # (㎏): kg
"\u3390", # (㎐): Hz
"\u3391", # (㎑): kHz
"\u3392", # (㎒): MHz
"\u3393", # (㎓): GHz
"\u3394", # (㎔): THz
"\u3396", # (㎖): ml
"\u3397", # (㎗): dl
"\u3398", # (㎘): kl
"\u3399", # (㎙): fm
"\u339A", # (㎚): nm
"\u339C", # (㎜): mm
"\u339D", # (㎝): cm
"\u339E", # (㎞): km
"\u33A9", # (㎩): Pa
"\u33AA", # (㎪): kPa
"\u33AB", # (㎫): MPa
"\u33AC", # (㎬): GPa
"\u33AD", # (㎭): rad
"\u33B0", # (㎰): ps
"\u33B1", # (㎱): ns
"\u33B3", # (㎳): ms
"\u33B4", # (㎴): pV
"\u33B5", # (㎵): nV
"\u33B7", # (㎷): mV
"\u33B8", # (㎸): kV
"\u33B9", # (㎹): MV
"\u33BA", # (㎺): pW
"\u33BB", # (㎻): nW
"\u33BD", # (㎽): mW
"\u33BE", # (㎾): kW
"\u33BF", # (㎿): MW
"\u33C3", # (㏃): Bq
"\u33C4", # (㏄): cc
"\u33C5", # (㏅): cd
"\u33C8", # (㏈): dB
"\u33C9", # (㏉): Gy
"\u33CA", # (㏊): ha
"\u33CB", # (㏋): HP
"\u33CC", # (㏌): in
"\u33CD", # (㏍): KK
"\u33CE", # (㏎): KM
"\u33CF", # (㏏): kt
"\u33D0", # (㏐): lm
"\u33D1", # (㏑): ln
"\u33D2", # (㏒): log
"\u33D3", # (㏓): lx
"\u33D4", # (㏔): mb
"\u33D5", # (㏕): mil
"\u33D6", # (㏖): mol
"\u33D7", # (㏗): PH
"\u33D9", # (㏙): PPM
"\u33DA", # (㏚): PR
"\u33DB", # (㏛): sr
"\u33DC", # (㏜): Sv
"\u33DD", # (㏝): Wb
"\u33FF", # (㏿): gal
"\uFB00", # (ff): ff
"\uFB01", # (fi): fi
"\uFB02", # (fl): fl
"\uFB03", # (ffi): ffi
"\uFB04", # (ffl): ffl
"\uFB05", # (ſt): st
"\uFB06", # (st): st
# "\u1F12D", # (🄭): CD
# "\u1F12E", # (🄮): WZ
# "\u1F14A", # (🅊): HV
# "\u1F14B", # (🅋): MV
# "\u1F14C", # (🅌): SD
# "\u1F14D", # (🅍): SS
# "\u1F14E", # (🅎): PPV
# "\u1F14F", # (🅏): WC
# "\u1F16A", # (🅪): MC
# "\u1F16B", # (🅫): MD
"\u1F19", #0 (🆐): DJ
"\u01C4", # (DŽ): DŽ
"\u01C5", # (Dž): Dž
"\u01C6", # (dž): dž
]

end

关于Ruby:如何仅从 unicode 文本中分解打印连字?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/70778295/

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