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javascript - 如何在 Canvas 上没有新绘图的情况下录制 Canvas + 音频

转载 作者:行者123 更新时间:2023-12-05 04:35:38 26 4
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我想录制一段在 HTML Canvas 上运行的脚本的视频,同时录制来自麦克风的音频。我正在使用 canvas.captureStream() 从 Canvas 创建视频流。然后,我从 getUserMedia() 创建一个音频流,并将两个流混合在一个流中,然后传递给一个新的 MediaRecorder

问题是,默认情况下,如果没有在 Canvas 上绘制任何内容, Canvas 流中将不会捕获任何帧。因此,在 Canvas 不活动的部分,视频和音频不同步。

我使用的代码如下所示:

let recording = false;
let mediaRecorder;
let chunks = [];

let newStream, canvasStream


let constrains = {
audio: {
channelCount: { ideal: 2, min: 1 },
sampleRate: 48000,
sampleSize: 16,
volume: 1,
echoCancellation: true,
noiseSuppression: true,
autoGainControl: true,
},
video: false
};

recButton.addEventListener("click", () => {
recording = !recording;
if (recording) {
recButton.textContent = "Click to Stop";
recButton.style.color = "red";
canvasStream = canvas.captureStream(40); // ---> captureStream()


navigator.mediaDevices.getUserMedia(constrains) // ---> audioStream
.then(audioStream => {

canvasStream.addTrack(audioStream.getTracks()[0]); // --> joint the two streams


mediaRecorder = new MediaRecorder(canvasStream, {
mimeType: 'video/webm; codecs=vp9',
// ignoreMutedMedia: false
});

mediaRecorder.ondataavailable = e => {
if (e.data.size > 0) {
chunks.push(e.data); // chunks = []; already defined above....
}
};
mediaRecorder.start();
})
.catch(err => {
console.log(err.name, err.message);
});
} else {
recButton.textContent = "Record";
recButton.style.color = "black";
mediaRecorder.stop()

stopTracks(canvasStream); // function stop defined below
console.log(mediaRecorder.state)
setTimeout(() => { // why this is necessary?
const blob = new Blob(chunks, {
type: "video/mp4"
});
const url = URL.createObjectURL(blob);
const a = document.createElement("a");
a.href = url;
a.download = "recording.mp4";
a.click();
URL.revokeObjectURL(url);
}, 200);
}
});

let stopTracks = stream => stream.getTracks().forEach(track => track.stop());

最佳答案

这有点像 Chrome 错误,因为即使视频轨道在这种情况下确实应该没有产生数据,但音频轨道有并且 MediaRecorder 应该捕获它。

解决此问题的唯一方法是至少在与调用 canvas.captureStream() 相同的绘图帧中在 Canvas 上执行新绘图。
对于 2D 上下文,较少干扰的方法是绘制一个透明的 1x1 矩形。

let recording = false;
let mediaRecorder;
const chunks = [];

let newStream, canvasStream

const constrains = {
audio: {
channelCount: { ideal: 2, min: 1 },
sampleRate: 48000,
sampleSize: 16,
volume: 1,
echoCancellation: true,
noiseSuppression: true,
autoGainControl: true,
},
video: false
};

recButton.addEventListener("click", () => {
recording = !recording;
if (recording) {
recButton.textContent = "Click to Stop";
recButton.style.color = "red";
canvasStream = canvas.captureStream(40);
// force activate the Canvas track
forceEmptyDrawing(canvas);
navigator.mediaDevices.getUserMedia(constrains) // ---> audioStream
.then(audioStream => {

canvasStream.addTrack(audioStream.getTracks()[0]); // --> joint the two streams
mediaRecorder = new MediaRecorder(canvasStream, {
// don't forget the audio codec
mimeType: "video/webm; codecs=vp9,opus",
// ignoreMutedMedia: false
});

mediaRecorder.ondataavailable = e => {
if (e.data.size > 0) {
chunks.push(e.data);
}
};
mediaRecorder.start(10);
})
.catch(err => {
console.log(err.name, err.message);
});
} else {
recButton.textContent = "Record";
recButton.style.color = "black";
mediaRecorder.stop()
// wait for the stop event
// don't rely on some magic timeout
mediaRecorder.onstop = () => {
// only when the recorder is completely stopped
// you can stop the tracks
stopTracks(canvasStream);
const blob = new Blob(chunks, {
type: "video/webm" // you asked for webm, not mp4
});
// just to verify we did record something
console.log(`recorded a ${ blob.size }b file`);
};
}
});

const stopTracks = stream => stream.getTracks().forEach(track => track.stop());

// draws a 1x1 transparent rectangle
function forceEmptyDrawing(canvas) {
const ctx = canvas.getContext("2d");
const alpha = ctx.globalAlpha;
ctx.globalAlpha = 0;
ctx.fillRect(0, 0, 1, 1);
ctx.globalAlpha = alpha;
}

As a fiddle因为 StackSnippets 不能使用 gUM(仅适用于 Chrome,Firefox 和 Safari 不支持提供的 mimeType)。

关于javascript - 如何在 Canvas 上没有新绘图的情况下录制 Canvas + 音频,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/70998884/

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