python - PEP 8 : E128 sometimes requires spaces and sometimes does not

Question

这post's answer建议 PEP 8: E128 要求在第一行之后的行上有空格，当它们都包含在括号内时。但是，对于 if 语句，情况似乎并非如此。您可以看到前三行没有警告，而后三行有警告，因为它们确实有一个空格:

我错过了什么吗？如果有帮助，我正在使用 Pycharm 社区版。

使用的代码:

def main(user_input):
    if (";" not in user_input
       and "DROP " not in user_input
       and "SELECT " not in user_input
        and "FROM " not in user_input
        and "DELETE " not in user_input
        and '"' not in user_input
        and ";" not in user_input
        and "=" not in user_input
        and ">" not in user_input
        and "<" not in user_input):
        pass
    else:
        exit()

编辑:因为有点困惑，这应该是正确的缩进:https://i.imgur.com/FqsJjkc.png这是 Pycharm 认为正确的一个 https://i.imgur.com/6DmejGi.png .除非我弄错了(可能是这样!)。

Answer 1

PEP-8 注意到 if ( 提供了一个自然的 4 空格缩进，它允许继续在括号之后开始:

if (";" not in user_input
    and "DROP " not in user_input
    ...

你的检查器显然不关心你是否写

if (";" not in user_input
   and "DROP " not in user_input
   ...

相反，但是，如果您确实使用该缩进，则必须继续使用相同的缩进。您的 FROM 行是偏离该缩进的第一行。

---

这很常见，PEP 甚至提供了一个链接到 this paragraph 的 anchor :

When the conditional part of an if-statement is long enough to requirethat it be written across multiple lines, it's worth noting that thecombination of a two character keyword (i.e. if), plus a single space,plus an opening parenthesis creates a natural 4-space indent for thesubsequent lines of the multiline conditional. This can produce avisual conflict with the indented suite of code nested inside theif-statement, which would also naturally be indented to 4 spaces. ThisPEP takes no explicit position on how (or whether) to further visuallydistinguish such conditional lines from the nested suite inside theif-statement. Acceptable options in this situation include, but arenot limited to:

# No extra indentation.
if (this_is_one_thing and
    that_is_another_thing):
    do_something()

# Add a comment, which will provide some distinction in editors
# supporting syntax highlighting.
if (this_is_one_thing and
    that_is_another_thing):
    # Since both conditions are true, we can frobnicate.
    do_something()

# Add some extra indentation on the conditional continuation line.
if (this_is_one_thing
        and that_is_another_thing):
    do_something()

(Also see the discussion of whether to break before or after binaryoperators below.)