php - 当服务器服务器使用 guzzle 重试中间件响应 200 个状态代码时，如何停止重试 HTTP 调用？

Question

以下代码抛出错误“参数 4 &$options expected to be a reference, value given”

此代码来自guzzle_retry_middleware#on-retry-callback

我想在收到 self::STATUS_DRAFT === $document->status 和 response 200

后停止 guzzle 重试调用

$listener = function(int $attemptNumber, float $delay, RequestInterface $request, array &$options, ?ResponseInterface $response)
{
    $document = \json_decode();

    if (self::STATUS_DRAFT === $document->status)
    {
        return $options['retry_enabled'] = false;
    }
};

$stack = HandlerStack::create();
$stack->push(GuzzleRetryMiddleware::factory([
    'on_retry_callback' => $listener,
    'retry_on_status'   =>[429, 503, 200]
]));

$response = $guzzleClient->get($url, ['handler' => $stack]);

Answer 1

这个测试代码对我来说似乎工作正常。我创建了一个随机吐出一个数字的请求，该数字用于重试回调。

我使用的是 PHP 7.3 以及最新版本的 Guzzle 和中间件。如果您收到有关 $options 变量的错误，请尝试在您的环境中隔离此代码并确认没有版本不匹配。

use GuzzleHttp\Client;
use GuzzleHttp\HandlerStack;
use GuzzleRetry\GuzzleRetryMiddleware;
use Psr\Http\Message\RequestInterface;
use Psr\Http\Message\ResponseInterface;

error_reporting(E_ALL);
ini_set('display_errors', '1');

$stack = HandlerStack::create();
$stack->push(GuzzleRetryMiddleware::factory());

$listener = function(int $attemptNumber, float $delay, RequestInterface &$request, array &$options, ResponseInterface $response) {
    $doc = json_decode($response->getBody()->getContents());
    echo "<br>Received {$doc->status} so ";

    if ($doc->status < 50) {
        $options['retry_enabled'] = false;
        echo "stopping";
        return;
    }
    echo "retrying";
};

$client = new Client([
    'handler' => $stack,
    'on_retry_callback' => $listener,
    'retry_on_status'   => [200]
]);

$response = $client->get('https://eouqfts30zafzos.m.pipedream.net/');

我得到了这个回复

Received 69 so retrying
Received 68 so retrying
Received 31 so stopping

这是我的 composer.json 文件

{
    "require": {
        "guzzlehttp/guzzle": "^7.0",
        "caseyamcl/guzzle_retry_middleware": "^2.7"
    }
}